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Calculus - Definition of the Limit - help

So the question is:

Use the definition of the limit to prove:
lim c = c
x→a

I've written, Given ε>0, δ=ε/0. If 0< 0< δ then IcI-c = Ic-cI = 0>0δ = 0(ε/0)=0

But it's supposed to so what did I do wrong?

Thanks!
Original post by Airess3
So the question is:

Use the definition of the limit to prove:
lim c = c
x→a

I've written, Given ε>0, δ=ε/0. If 0< 0< δ then IcI-c = Ic-cI = 0>0δ = 0(ε/0)=0

But it's supposed to so what did I do wrong?

Thanks!

You seem to have divided epsilon by zero? Also you have the line "if 0<0<δ0 < 0 < \delta", a condition which is never satisfied because 000 \geq 0.

Can you state the definition of "limit" for me first?

By the way, the pipe character | is much more comprehensible than I.
Original post by Smaug123
You seem to have divided epsilon by zero? Also you have the line "if 0<0<δ0 < 0 < \delta", a condition which is never satisfied because 000 \geq 0.

Can you state the definition of "limit" for me first?

By the way, the pipe character | is much more comprehensible than I.


Let f be a function defined by an open interval, containing 'a', except possibly not at 'a' itself. We say, the "limit as x approaches a is L", and write: lim(f(x))=L.
x→a
If for every ε greater than 0, there is delta greater than 0, such that if 0 is lesser than |x-a| lesser than delta then |f(x) -L| lesser than epsilon.
Reply 3
from your last bit, this is satisfied for every x , since:

f(x)L=cc=0<ϵ|f (x)-L| = |c-c|=0< \epsilon

take δ=ϵ\delta= \epsilon
(edited 9 years ago)
Original post by Hasufel
from your last bit, this is satisfied for every x , since:

f(x)L=cc=0<ϵ|f (x)-L| = |c-c|=0< \epsilon

take δ=ϵ\delta= \epsilon


I understand it now, thanks!

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