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Maths C1 Series and Sequences

Hi,
Im stuck on this question: "Prove that the (2n+1)th term of the sequence Un=n^2 -1 is a multiple of 4."

I've substituted the "(2n+1)" as "n" into the formula and got "U 2n+1=4n^2+4n+1-1" so i ended up with "U2n+1=4n^2+4n"... I don't know what to do from here on...

Help would be great, thanks
Original post by Arman47
Hi,
Im stuck on this question: "Prove that the (2n+1)th term of the sequence Un=n^2 -1 is a multiple of 4."

I've substituted the "(2n+1)" as "n" into the formula and got "U 2n+1=4n^2+4n+1-1" so i ended up with "U2n+1=4n^2+4n"... I don't know what to do from here on...

Help would be great, thanks


Moved to the maths forum for you :smile:
Original post by Arman47
Hi,
Im stuck on this question: "Prove that the (2n+1)th term of the sequence Un=n^2 -1 is a multiple of 4."

I've substituted the "(2n+1)" as "n" into the formula and got "U 2n+1=4n^2+4n+1-1" so i ended up with "U2n+1=4n^2+4n"... I don't know what to do from here on...

Help would be great, thanks


Are you saying that you have 4n2+4n4n^2 + 4n and you cannot show that it is a multiple of 4?
Reply 3
Original post by TenOfThem
Are you saying that you have 4n2+4n4n^2 + 4n and you cannot show that it is a multiple of 4?


In the answer section it says "Un=4n^2+4n" so i got confused because i ended up with "U2n+1=4n^2+4n"...
Reply 4
Original post by She-Ra
Moved to the maths forum for you :smile:

Thanks ^___^
Original post by Arman47
In the answer section it says "Un=4n^2+4n" so i got confused because i ended up with "U2n+1=4n^2+4n"...


U2n+1=4n2+4n=4(n2+n)U_{2n+1} = 4n^2 + 4n = 4(n^2 + n)

Is the answer that you are looking for
(edited 9 years ago)
Reply 6
Thanks :smile:

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