The Student Room Group

A2 help please

Can you help me please

question: the diagram shows the curve y = 6/(3x+1)^(1/2). The shaded region is bound by the curve and the lines
x=2 x=9 and y= 0

ii) the shaded region is rotated completely about the x- axis. Show that the volume of the solid produced can be written in the form of k(ln)2 where the exact value of the constant k is to be determined.
Original post by ADotCross
Can you help me please

question: the diagram shows the curve y = 6/(3x+1)^(1/2). The shaded region is bound by the curve and the lines
x=2 x=9 and y= 0

ii) the shaded region is rotated completely about the x- axis. Show that the volume of the solid produced can be written in the form of k(ln)2 where the exact value of the constant k is to be determined.


Could you show some working or say what you have tried?
Reply 2
Original post by Mr M
Could you show some working or say what you have tried?


So I used the formula (pi) (intergrate) y^2

so y^2= 36/(3x+1)

then intergration

= (pi)36(1/3) x (1/3x+1)

then simlplify

12(pi)/3x +1

this is is where I got to ( I think I made a mistake in the intergration but dunno where)
Original post by ADotCross
So I used the formula (pi) (intergrate) y^2

so y^2= 36/(3x+1)

then intergration

= (pi)36(1/3) x (1/3x+1)

then simlplify

12(pi)/3x +1

this is is where I got to ( I think I made a mistake in the intergration but dunno where)


Indeed - do you know what 1xdx\displaystyle \int \dfrac{1}{x} dx is
Reply 4
Original post by TenOfThem
Indeed - do you know what 1xdx\displaystyle \int \dfrac{1}{x} dx is



Ln(x)

Should it be 12(pi)ln(3x+1) ?
(edited 9 years ago)
Original post by ADotCross
Ln(x)


So, why is the no ln(3x+1) in your integration since you were integrating 13x+1\dfrac{1}{3x+1}
Original post by ADotCross
Ln(x)

Should it be 12(pi)ln(3x+1) ?


yes
Reply 7
How do I simplify this ?
Reply 8
leaving out the factor of 12Pi for now, what is : F(9)F(2)F(9)-F(2) ?

(use the law of logs: ln(ab)=bln(a)ln(a^{b})= bln(a)
Original post by ADotCross
How do I simplify this ?


Put 9 and 2 in
Reply 10
So would it be

12(pi) x (ln28 -ln7) ?
yup - now simplify the logs: ln(a)-ln(b) = ln(a/b)

(sorry TenofThem - hijacked your answer somewhat)
Reply 12
I suck with logs....

so then that would happen right ?

12(pi)(ln28/7) ?
Reply 13
Can I make it into 12(pi) ln4 ?
Reply 14
Original post by ADotCross
Can I make it into 12(pi) ln4 ?


Yes, and you can write ln4 in terms of ln2 :smile:
Reply 15
So it would become

12(pi)(ln2+ln2)
=
12(pi)ln2 + 12(pi)ln2

do I add or was it times the 12 together

so so it would make it 24(pi)ln2 or is it 144(pi)ln2 ?
Reply 16
Thank you guys so much !!!

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