Q: express 3sin+4cos in the form Rsin(theata + alpha). And 0< alpha < 90 degrees
(!)= theata
(?)= alpha
ii) hence, solve the equation 3sin(!) + 4cos(!) +1 = 0
solutions between -180 and 180
Ive done part1 which gives the angle 53.1.....
the he second part I'm stuck with as I don't think I'm correct, here is my working out for part 2
3sin(!) +4cos(!) = inverse tan(4/3)
therefore re can I just make it
tan = 4/3 -1
inverse tan = 18.4349.....
i have no clue what I'm doing thus me guessing what to do...