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C4 polynomials

Hi I have attempted question 5 and also rechecked my work but I can't figure out where I've gone wrong. My answer is 278/27 but the book says 270/8

I have attached my working out

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Original post by the_googly


You are correct: 278/27.
Reply 3
Original post by Smaug123
You are correct: 278/27.


Cool so the book is wrong
Original post by the_googly
Cool so the book is wrong

So it would appear.
Reply 5
Hi on question 4b I'm stuck on integrating x/x+1 (which I end up with in working out). Please help

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Original post by the_googly
Hi on question 4b I'm stuck on integrating x/x+1 (which I end up with in working out). Please help

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xx+1=(x+1)1x+1=11x+1\displaystyle \frac{x}{x+1}=\frac{(x+1)-1}{x+1}=1-\frac{1}{x+1}
You'd actually have been better advised to use the correct form of partial fractions (or perform the FULL division) at outset.

x(2x+1)x+1=Ax+B+Cx+1\displaystyle \frac{x(2x+1)}{x+1}=Ax+B+\frac{C}{x+1}
(edited 9 years ago)
Reply 9
Original post by Mr M
You'd actually have been better advised to use the correct form of partial fractions (or perform the division) at outset.

x(2x+1)x+1=Ax+B+Cx+1\displaystyle \frac{x(2x+1)}{x+1}=Ax+B+\frac{C}{x+1}


I have not seen anything like the above in my book:confused:
Original post by the_googly
I have not seen anything like the above in my book:confused:


Possibly not but you certainly know how to divide a quadratic by a linear term.

The form I provided is correct as the quotient must be linear.
Reply 11
That's what I've been given in the book. From My understanding when the fraction is in proper you use polynomial long division?

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Original post by the_googly
That's what I've been given in the book. From My understanding when the fraction is in proper you use polynomial long division?

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Improper.

Yes that's what I just did.

Edit: You do realise you didn't complete your long division?
(edited 9 years ago)
Reply 13
Original post by Mr M
Improper.

Yes that's what I just did.


Didn't I do that?
Reply 14
Original post by Mr M
Improper.

Yes that's what I just did.

Edit: You do realise you didn't complete your long division?


No I don't lol
Original post by the_googly
Didn't I do that?


No you didn't complete the division. You left yourself with another improper fraction.

x/(x+1) is improper because the numerator is not of lower degree than the denominator.
(edited 9 years ago)
Original post by the_googly
How about now?

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Nope.

0110 - - 1 \neq -1
Reply 18
Original post by Mr M
Nope.

0110 - - 1 \neq -1


Ok thanks.
Reply 19
Also struggling on question 3A lol

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