Gibbs Energy Question
Hi all,
Looking for some help with the later parts of this question:
I have answers for a, b and c.
For D, I thought about using the equation Delta G = Delta Go + RTln(B/A) ? But I'm not sure. And then % yield will be B/A * 100?
For E, I figured, if the method for D is correct, that increasing T, the value for B will increase. (By looking at how you calculated B in the first place)
For F, is seting up two van't hoff equations for 25 degrees and 50 degrees, subtract one from the other and find K2. (ln(k1/k2)=-deltHO/R(1/t1-1/t2).
Pretty stumped by the latter half of this question, so any help will be appreciated!
Looking for some help with the later parts of this question:
I have answers for a, b and c.
For D, I thought about using the equation Delta G = Delta Go + RTln(B/A) ? But I'm not sure. And then % yield will be B/A * 100?
For E, I figured, if the method for D is correct, that increasing T, the value for B will increase. (By looking at how you calculated B in the first place)
For F, is seting up two van't hoff equations for 25 degrees and 50 degrees, subtract one from the other and find K2. (ln(k1/k2)=-deltHO/R(1/t1-1/t2).
Pretty stumped by the latter half of this question, so any help will be appreciated!
Original post by Sam_Chem
Hi all,
Looking for some help with the later parts of this question:
I have answers for a, b and c.
For D, I thought about using the equation Delta G = Delta Go + RTln(B/A) ? But I'm not sure. And then % yield will be B/A * 100?
For E, I figured, if the method for D is correct, that increasing T, the value for B will increase. (By looking at how you calculated B in the first place)
For F, is seting up two van't hoff equations for 25 degrees and 50 degrees, subtract one from the other and find K2. (ln(k1/k2)=-deltHO/R(1/t1-1/t2).
Pretty stumped by the latter half of this question, so any help will be appreciated!
Looking for some help with the later parts of this question:
I have answers for a, b and c.
For D, I thought about using the equation Delta G = Delta Go + RTln(B/A) ? But I'm not sure. And then % yield will be B/A * 100?
For E, I figured, if the method for D is correct, that increasing T, the value for B will increase. (By looking at how you calculated B in the first place)
For F, is seting up two van't hoff equations for 25 degrees and 50 degrees, subtract one from the other and find K2. (ln(k1/k2)=-deltHO/R(1/t1-1/t2).
Pretty stumped by the latter half of this question, so any help will be appreciated!
Too complicated.
You are given the equilibrium constant in the question...
A <==> B
You have the initial moles.
The equilibrium moles of A = initial - x
you see where to go?
Original post by charco
Too complicated.
You are given the equilibrium constant in the question...
A <==> B
You have the initial moles.
The equilibrium moles of A = initial - x
you see where to go?
You are given the equilibrium constant in the question...
A <==> B
You have the initial moles.
The equilibrium moles of A = initial - x
you see where to go?
Not entirely
could you explain a bit more please?Original post by Sam_Chem
Not entirely could you explain a bit more please?
could you explain a bit more please?What are your answers for a, b and c?
Original post by KombatWombat
What are your answers for a, b and c?
(This where I realise its all gone wrong haha!)
A) K=/[A]
B) Delta G = 0, Delta Go = 1426.5Jmol-1
C)102.6Jmol-1K-1- +ve dirsorder is increasing, therefore favouring the forward reaction
Original post by Sam_Chem
(This where I realise its all gone wrong haha!)
A) K=/[A]
B) Delta G = 0, Delta Go = 1426.5Jmol-1
C)102.6Jmol-1K-1- +ve dirsorder is increasing, therefore favouring the forward reaction
A) K=/[A]
B) Delta G = 0, Delta Go = 1426.5Jmol-1
C)102.6Jmol-1K-1- +ve dirsorder is increasing, therefore favouring the forward reaction
No, they're all good!
You know that in total there'll be 0.5 M of A and B, i.e. [A]+=0.5 M
K=0.56 = /[A] =/(0.5 M - )
Solve that to give you , and get your percentage yield
For e and f, you know the entropy, assume enthalpy is constant with temperature, and you can work out a new value of ∆G and so K. I'd rather do f first because that tells you the answer to e, maybe they want you to e with some handwaving.
(edited 9 years ago)
Original post by KombatWombat
No, they're all good!
You know that in total there'll be 0.5 M of A and B, i.e. [A]+=0.5 M
K=0.56 = /[A] =/(0.5 M - )
Solve that to give you , and get your percentage yield
For e and f, you know the entropy, assume enthalpy is constant with temperature, and you can work out a new value of ∆G and so K. I'd rather do f first because that tells you the answer to e, maybe they want you to e with some handwaving.
You know that in total there'll be 0.5 M of A and B, i.e. [A]+=0.5 M
K=0.56 = /[A] =/(0.5 M - )
Solve that to give you , and get your percentage yield
For e and f, you know the entropy, assume enthalpy is constant with temperature, and you can work out a new value of ∆G and so K. I'd rather do f first because that tells you the answer to e, maybe they want you to e with some handwaving.
So = 0.179M?
%Yield will be 35.8%
F) Came out as 1.52 (forgot units) What about the second part though? D:
E) I imagine part of the answer for E will involve the previous answers, but not sure how to explain it? It does seem intuitive that temp will increase % yield.]
(edited 9 years ago)
Original post by Sam_Chem
So = 0.179M?
%Yield will be 35.8%
F) Came out as 1.52 (forgot units) What about the second part though? D:
E) I imagine part of the answer for E will involve the previous answers, but not sure how to explain it? It does seem intuitive that temp will increase % yield.]
%Yield will be 35.8%
F) Came out as 1.52 (forgot units) What about the second part though? D:
E) I imagine part of the answer for E will involve the previous answers, but not sure how to explain it? It does seem intuitive that temp will increase % yield.]
What are the units of [A] and ? This tells you the units of K. Your second value of K will also have the same units as given in the question!
You can calculate at 50°C in the same way as you did before, and then get a new percentage yield to get the second part of f, and this also tells you e.
(Actually, I should also point out that using Van 't Hoff is fine too, to calculate your second value of K. It's essentially doing the same thing. I prefer not to since it's another formula to remember).
And to explain what's happening in e, how does gibbs energy change with temperature?
Original post by KombatWombat
What are the units of [A] and ? This tells you the units of K. Your second value of K will also have the same units as given in the question!
You can calculate at 50°C in the same way as you did before, and then get a new percentage yield to get the second part of f, and this also tells you e.
(Actually, I should also point out that using Van 't Hoff is fine too, to calculate your second value of K. It's essentially doing the same thing. I prefer not to since it's another formula to remember).
And to explain what's happening in e, how does gibbs energy change with temperature?
You can calculate at 50°C in the same way as you did before, and then get a new percentage yield to get the second part of f, and this also tells you e.
(Actually, I should also point out that using Van 't Hoff is fine too, to calculate your second value of K. It's essentially doing the same thing. I prefer not to since it's another formula to remember).
And to explain what's happening in e, how does gibbs energy change with temperature?
Ah I see.
I'm more familar with the Van't Hoff method so I'll probably use that. Is the answers I put in the previous post the same as what you got?
Well, entropy is positive, so looking at delta G = delta H - T delta S, so as temperature increases gibbs free energy is decreased, so max product yield is decreased?
Reaction is endothermic - standard enthalpy change is positive - so increases to temperature increases the equilibrium constant K, thus max yield will increase.
It definitely makes sense im just trying to make sense of getting the first part of D. Also, part E is throwing me off; struggling to understand this sufficiently to apply this to different examples, can anyone summarise this idea?
(edited 9 years ago)
[QUOTE="KombatWombat;52700517"]What are the units of [A] and ? This tells you the units of K. Your second value of K will also have the same units as given in the question!
Not sure how many times i've had to say this on TSR now but here we go...
K IS DIMENSIONLESS. ALWAYS.
Original post by Sam_Chem
F) Came out as 1.52 (forgot units) What about the second part though? D:
F) Came out as 1.52 (forgot units) What about the second part though? D:
Not sure how many times i've had to say this on TSR now but here we go...
K IS DIMENSIONLESS. ALWAYS.
Original post by langlitz
Not sure how many times i've had to say this on TSR now but here we go...
K IS DIMENSIONLESS. ALWAYS.
K IS DIMENSIONLESS. ALWAYS.
Yeah... my lecturer put so much emphasis on units for everything I was just on auto pilot looking for units that are not there, I guess if in doubt put the units of stuff in the equation. My mistake
Original post by langlitz
Not sure how many times i've had to say this on TSR now but here we go...
K IS DIMENSIONLESS. ALWAYS.
K IS DIMENSIONLESS. ALWAYS.
Yes, but ...
.. the exam boards expect the students to work out the 'dimensions' assuming that the concentrations are used for the law of mass action and not activities.
A' level (and IB) students have to be able to jump through the required hoops even if they are incorrect.
Original post by charco
Yes, but ...
.. the exam boards expect the students to work out the 'dimensions' assuming that the concentrations are used for the law of mass action and not activities.
A' level (and IB) students have to be able to jump through the required hoops even if they are incorrect.
.. the exam boards expect the students to work out the 'dimensions' assuming that the concentrations are used for the law of mass action and not activities.
A' level (and IB) students have to be able to jump through the required hoops even if they are incorrect.
The label says undergraduate and he refers to his lecturer...?
Original post by langlitz
Not sure how many times i've had to say this on TSR now but here we go...
K IS DIMENSIONLESS. ALWAYS.
K IS DIMENSIONLESS. ALWAYS.
Yep, quite right, my apologies!
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