I thought you only add a polynomial when the fraction is an improper fraction?
Why isn't it
A/(x^2 + 1) + B/(x-1) + C/(x+1)
brianeverit has given you the correct form ...
the reason for what you are asking you may not understand at present but here it comes... when you divide by an irreducible quadratic the most general form for the remainder is a linear expression
the reason for what you are asking you may not understand at present but here it comes... when you divide by an irreducible quadratic the most general form for the remainder is a linear expression
Ok I understand now. Just one last question... when differentiating sin(2x) the answer is 2cos(2x) but when you differentiate 2sin(-2x) the answer is -2cos(2x) why isn't it -2cos(-2x) ?
Ok I understand now. Just one last question... when differentiating sin(2x) the answer is 2cos(2x) but when you differentiate 2sin(-2x) the answer is -2cos(2x) why isn't it -2cos(-2x) ?
Ok I understand now. Just one last question... when differentiating sin(2x) the answer is 2cos(2x) but when you differentiate 2sin(-2x) the answer is -2cos(2x) why isn't it -2cos(-2x) ?
dxd[2sin(−2x)]=−4cos(2x)
Since cosine is an even function. That is f(x)=cosx has the property that f(x)=f(−x).