The Student Room Group

C3 - trig

Hello, I'm stuck/confused with the following.

Tan^2X+2tanx+1 express in terms of cotx. I think it's (cot^2x)+(1/2cotx)+1. But there's a devil in me trying to make believe its (cot^2x)+(2cotx)+1 - surely this can't be right? Which one is it:angry:

Scroll to see replies

Reply 1
Original post by Cool-Light
Hello, I'm stuck/confused with the following.

Tan^2X+2tanx+1 express in terms of cotx. I think it's (cot^2x)+(1/2cotx)+1. But there's a devil in me trying to make believe its (cot^2x)+(2cotx)+1 - surely this can't be right? Which one is it:angry:


I do not follow your argument
would you be as kind as to post your working?
Reply 2
Original post by Cool-Light
Hello, I'm stuck/confused with the following.

Tan^2X+2tanx+1 express in terms of cotx. I think it's (cot^2x)+(1/2cotx)+1. But there's a devil in me trying to make believe its (cot^2x)+(2cotx)+1 - surely this can't be right? Which one is it:angry:


2tanx is simply (2)x(tanx). You can then change (tanx) to (1/cotx) so you end up with (2)x(1/cotx) which is (2/cotx). I think :smile:

(the 'x's outside the brackets being multiplication signs rather than the variable x)
(edited 9 years ago)
Original post by Cool-Light
Hello, I'm stuck/confused with the following.

Tan^2X+2tanx+1 express in terms of cotx. I think it's (cot^2x)+(1/2cotx)+1. But there's a devil in me trying to make believe its (cot^2x)+(2cotx)+1 - surely this can't be right? Which one is it:angry:


tanx=1cotx\tan x = \frac{1}{\cot x}
tan2x+2tanx+1=cot2x+2cot1x+1 \therefore \tan^{2} x + 2\tan x + 1 = \cot^{-2} x + 2 \cot^{-1} x + 1
Reply 4
Original post by TeeEm
I do not follow your argument
would you be as kind as to post your working?


Ahhh, here's the original question manipulated by me. "Simplify the following expressions to a single term"

Question: (tan^4x)+(2tan^x)+1, please don't solve it, it's one of my homework questions, I just need a hint. So I tried that up there in order to experiment and see where I get...
Reply 5
Original post by morgan8002
tanx=1cotx\tan x = \frac{1}{\cot x}
tan2x+2tanx+1=cot2x+2cot1x+1 \therefore \tan^{2} x + 2\tan x + 1 = \cot^{-2} x + 2 \cot^{-1} x + 1

Oh, so the devil turned out to be angel :smile:. Thank you for clearing the misconception
Reply 6
Original post by Cool-Light
Ahhh, here's the original question manipulated by me. "Simplify the following expressions to a single term"

Question: (tan^4x)+(2tan^x)+1, please don't solve it, it's one of my homework questions, I just need a hint. So I tried that up there in order to experiment and see where I get...


look at post 4
is what morgan8002 has written your question because what you have typed is ambiguous
Reply 7
Wait what...?
Reply 8
Original post by TeeEm
look at post 4
is what morgan8002 has written your question because what you have typed is ambiguous

So there's more than one way of writing it?
Original post by Cool-Light
Ahhh, here's the original question manipulated by me. "Simplify the following expressions to a single term"

Question: (tan^4x)+(2tan^x)+1, please don't solve it, it's one of my homework questions, I just need a hint. So I tried that up there in order to experiment and see where I get...

does tan^4x mean tan4x\tan^{4} x? what about 2tan^x?
Reply 10
Original post by Cool-Light
So there's more than one way of writing it?





straitjacket-vector-823041.jpg



NO!


read this please

http://www.thestudentroom.co.uk/showthread.php?t=2873737
Reply 11


Haha, that image made my day. I'll write it for u n upload
Reply 12
Original post by Cool-Light
Haha, that image made my day. I'll write it for u n upload


thanks
:smile:
Reply 13
Hopefully it posted...
Original post by Cool-Light
Hopefully it posted...


You can't legally derive the second expression.
Think about how you can get it in a form where you can use the standard trig identities.
(edited 9 years ago)
Reply 15
Original post by morgan8002
You can't legally derive the second expression.
Think about how you can get it in a form where you can use the standard trig identities.

Omfg!! Thank you!!!!! I'm an idiot, if we were to factorise the image I uploaded without the illegal move we would get this:
Original post by Cool-Light
Omfg!! Thank you!!!!! I'm an idiot, if we were to factorise the image I uploaded without the illegal move we would get this:

I don't see an image, but factorising is the way to go. Do you see where to go now?
(edited 9 years ago)
Reply 17
Original post by morgan8002
You can't legally derive the second expression.
Think about how you can get it in a form where you can use the standard trig identities.


And true, I just did it to view my understanding from an easier perspective if that makes sense?
Reply 18
Did it upload
Reply 19
Sorry my net and my phone decides to freeze at certain points, f@k!

Quick Reply

Latest