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Area of sector of circle??

Need
(edited 7 years ago)
Original post by iamspiderman


Need help answering this question.....


(a) Area of segment OPQ-area of segment OXY
Original post by iamspiderman


Need help answering this question.....


Area of a sector is angle/360 x the area of the circle
Original post by TenOfThem
Area of a sector is angle/360 x the area of the circle



Ok so would it be:

Area of full circle
3.14 x 20^2 = 1256

Area of sector = 65/360 x 1256
= 226.7

Is this right??
Original post by iamspiderman
Ok so would it be:

Area of full circle
3.14 x 20^2 = 1256

Area of sector = 65/360 x 1256
= 226.7

Is this right??


For OPQ yes
Original post by TenOfThem
For OPQ yes


Thanks for replying

Ok but how would I find the area for XPQY?
Original post by iamspiderman
Thanks for replying

Ok but how would I find the area for XPQY?


You have the big sector so you need to find the small sector and take it away
Original post by TenOfThem
You have the big sector so you need to find the small sector and take it away


Ok,for XPQY I did:

Area= 3.14 x 10^2 = 314.16( I halved the radius)

Area of sector= 65/360 x 314.16 = 56.72

So OPQ - XPQY
226.7 - 56.72= 169.98

Is this right ?
Original post by iamspiderman
Ok,for XPQY I did:

Area= 3.14 x 10^2 = 314.16( I halved the radius)

Area of sector= 65/360 x 314.16 = 56.72

So OPQ - XPQY
226.7 - 56.72= 169.98

Is this right ?


Yes

Though you meant OPQ-OXY
(edited 9 years ago)

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