Ah never mind, I see what you've done (divided through by 3x?). If so, instead subtract both sides by 3x so that you get 6x = 0. Then solving for x, you get x = 0.
By dividing though by x (or 3x), you essentially divide through by zero which ruins things.
It's asking to show that (x, y) is (0, 0) so you can make the equations equal to each other to get 9x=3x. Then for what value of x would this equation hold? Next, what value of y do you get when you substitute the newly found value of x into either equation?
Ah never mind, I see what you've done (divided through by 3x?). If so, instead subtract both sides by 3x so that you get 6x = 0. Then solving for x, you get x = 0.
By dividing though by x (or 3x), you essentially divide through by zero which ruins things.
(Also, just as an aside, 3x/3x = 1 )
Omg subtracting, of course! How obvious ariejkhjGH ugh that's so annoying! ahah, thank you so much!
If you don't mind, could you see where I went wrong in these two questions (sorry about the blurry photos and my messy handwriting) :P