Help with Stats Question!

Ok ... You are getting there ������

Now ... What do you do with probabilities if all 5 things need to happen?

I HAVE IT!!!

8/11x7x10 +3/11x2/10x1/9 -5/11 = 2/33

Erm, no

What did you do there?

Oh then I don't know what to do next then ;/


Posted from TSR Mobile

Ok ... No worries

If you want things to happen together you have to multiply the probabilities

So the probability of MMFFF = 8/11 x 7/10 x 3/9 x 2/8 x 1/7 = 2/330

Now ... The same probability occurs for different arrangements of MMFFF

So the probability of, for example, MFFMF is also 2/330

There are 10 arrangements of MMFFF so 10 x 2/330 = 2/33

However ... My new question is ... Do you know how I worked out the 10 for the different arrangements?

Is it because there is 5 on each stall and there is 2 stalls, so times them together gives you 10?

No

Have you done the binomial expansion?

Or

Have you been introduced to the nCr function

Yes, how does that relate?

Because nCr gives you the number of arrangements when you have n items, r of one type

So arrangements of MMFFF is 5C2 (or 5C3)

Oh yeah ok, I get that

So
P(A) = 8/11 x 7/10 x 3/9 x 2/8 x 1/7 x 5C2 = 2/33

I cant thank you enough, I would have never came to working out the solution without your help. Thanks for all your help and your patients