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Maths help please C2 circle theorems

A line, l,has equation y=mx and a circle,C, has equation x2+ y -6x -4y +9 =0
a) Given that l is a tangent to C, find the possible values of m.
b)Find the range of values of m, given that l intersects C in two distinct points
c)Find the range of values of m, given that l and C do not intersect.

please leave working out

many thanks,

keefe

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Reply 1
Original post by Kexfe
A line, l,has equation y=mx and a circle,C, has equation x2+ y -6x -4y +9 =0
a) Given that l is a tangent to C, find the possible values of m.
b)Find the range of values of m, given that l intersects C in two distinct points
c)Find the range of values of m, given that l and C do not intersect.

please leave working out

many thanks,

keefe


Have you managed to get started on this? What have you tried so far?
Reply 2
Here you go:

The discriminant inequality signs in parts b) and c) should be swapped.
(edited 9 years ago)
Reply 3
Original post by Kexfe
A line, l,has equation y=mx and a circle,C, has equation x2+ y -6x -4y +9 =0
a) Given that l is a tangent to C, find the possible values of m.
b)Find the range of values of m, given that l intersects C in two distinct points
c)Find the range of values of m, given that l and C do not intersect.

please leave working out

many thanks,

keefe


Original post by SH0405
Here you go:



Make sure you understand my working, rather than just writing it down.
(edited 9 years ago)
Reply 4
Original post by SH0405
Make sure you understand my working, rather than just writing it down.


Are you aware of the rules regarding not posting full solutions in this forum?
Reply 5
Original post by davros
Are you aware of the rules regarding not posting full solutions in this forum?


Nope.

If I were, I wouldn't have posted a full solution.

Sorry.
Original post by SH0405
Nope.

If I were, I wouldn't have posted a full solution.

Sorry.


Could you please delete your posts showing full solutions .. Thanks


Also .... For your own benefit .... You parts b and c are the wrong way round
(edited 9 years ago)
Reply 7
Original post by TenOfThem
Could you please delete your posts showing full solutions .. Thanks


Also .... For your own benefit .... You parts b and c are the wrong way round


Are they? I don't think so.
(edited 9 years ago)
Reply 8
Lovely handwriting
Original post by SH0405
Here you go:

(edited 9 years ago)
Reply 9
Original post by naxiv
Lovely handwriting


:redface:
Original post by SH0405
Are they? I don't think so.


Yes

I take it you will not be removing your solutions
Reply 11
Original post by TenOfThem
Yes

I take it you will not be removing your solutions


Could you explain first? Pleeeaassseeee?
(edited 9 years ago)
Original post by SH0405
Could you explain first? Pleeeaassseeee?


Explain what

b^2-4ac >0 gives 2 solutions
(edited 9 years ago)
Original post by SH0405
...

Really lovely handwriting.
Reply 14
Original post by TenOfThem
Explain what

b^2-4ac >0 gives 2 solutions


I didn't write that. There's an inequality sign error later on, but I'm pretty sure the parts and answers are fine.

Edit. Ah, good. My answers were correct.
(edited 9 years ago)
Original post by SH0405
I didn't write that. There's an inequality sign error later on, but I'm pretty sure the parts and answers are fine.


I know that you didn't write that

Hence your error
Reply 16
Original post by naxiv
Lovely handwriting


Original post by MathMeister
Really lovely handwriting.


Really? Everyone at school keeps saying that, but I didn't think it was that great. :/
Reply 17
Original post by TenOfThem
I know that you didn't write that

Hence your error


My answers were (thankfully) still correct though.
Original post by SH0405
My answers were (thankfully) still correct though.


No

They are wrong
Reply 19
Original post by TenOfThem
No

They are wrong


No they're not. I know I wrote down the wrong signs, but in the lines where I go from the discriminant inequalities I jump a few stages in my head. I didn't know at the time that I had got the inequality signs wrong remember. So my final answers are correct.

The stage that I did in my head could, admittedly, have done with some written workings (well, in one sense), but it all boils down to reversing an inequality sign when one divides through by a negative. I've checked it graphically too. And after one has completed part a), it's not hard to logically deduce the answers to parts b) and c), which is why my written workings suffered, but not ​my answers.

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