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Can anyone help me with this maths question?

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1422108999761.jpg27.2KB
Reply 1
Avatar for Phichi
Phichi
11
Original post by Minzky


What exactly do you need help on?


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Reply 2
Avatar for Minzky
Minzky
OP
7
Find the length pr in the photo u sent

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Reply 3
Avatar for Aph
Aph
22
Original post by Minzky
Find the length pr in the photo u sent

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Calculate the length of each of the 4 base parts then apply pythagorous.
Reply 4
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Minzky
OP
7
Pythagoras is for right angle triangles though?
Reply 5
Avatar for Aph
Aph
22
Original post by Minzky
Pythagoras is for right angle triangles though?

APR is a right-angled triangle.
Original post by Aph
APR is a right-angled triangle.


No it isnt
Original post by Aph
Calculate the length of each of the 4 base parts then apply pythagorous.


How would you find each base part

If you could do that then you would know AP so you would know AR
Reply 8
Avatar for Aph
Aph
22
Original post by TenOfThem
No it isnt

Yes it is
Original post by TenOfThem
How would you find each base part

If you could do that then you would know AP so you would know AR
the lines AB and BC are the same length and the angles are the same across the line as each part is the same length you know all the base parts are the same length.
Original post by Aph
Yes it is
the lines AB and BC are the same length and the angles are the same across the line as each part is the same length you know all the base parts are the same length.


You are mistaken regarding the right angled triangle ... The angle BAC is not 45 degrees


Regarding the base parts ... I can not see any easy way to calculate them ... Perhaps you can suggest a method
Reply 10
Avatar for Phichi
Phichi
11
Original post by Aph
Yes it is


No it really isn't.
Reply 11
Avatar for Aph
Aph
22
Original post by TenOfThem
You are mistaken regarding the right angled triangle ... The angle BAC is not 45 degrees


Regarding the base parts ... I can not see any easy way to calculate them ... Perhaps you can suggest a method

I never said it was but APR is. That's what I said.

its simple:facepalm: can you not see that the lines AP=R(dotted line) because they are identical triangles but RB(dotted line) is sitting on a square so that the bases are the same?!
Reply 12
Avatar for Aph
Aph
22
Original post by Phichi
No it really isn't.

Look ate the similar triangles:facepalm:
Original post by Aph
I never said it was but APR is. That's what I said.



APR is an isosceles triangle, the angle is not 45 ... Can you explain why you think it is right angled
Original post by Aph

its simple:facepalm: can you not see that the lines AP=R(dotted line) because they are identical triangles but RB(dotted line) is sitting on a square so that the bases are the same?!


This does not actually make sense

If the angle APR were 90 degrees then the base would be split equally into 4.5cm
But it isn't ... So I am still wondering how you are working out the base lengths
Original post by Aph
APR is a right-angled triangle.

It really, really isn't. Read the question again.
Reply 16
Avatar for Aph
Aph
22
Original post by TenOfThem
APR is an isosceles triangle, the angle is not 45 ... Can you explain why you think it is right angled

ABT is right angled agreed? And APR is a similar triangle correct? Because it has a common angle PAR and has sides of proportional dimension as AB=10 and AR=5
you know the roof is symmetrical so AT=AC, AC=18 so AT=9
and AT=2AP
Original post by Aph
ABT is right angled agreed? And APR is a similar triangle correct? Because it has a common angle PAR and has sides of proportional dimension as AB=10 and AR=5
you know the roof is symmetrical so AT=AC, AC=18 so AT=9
and AT=2AP


No

APR is not a similar triangle

It has one common angle ... And one pair of proportional sides



It could only be similar if APR were right angled and we have established that it is not
Original post by Aph
AT=2AP

Just because it looks roughly like that in the picture does not mean it is true...
(edited 9 years ago)
Reply 19
Avatar for Aph
Aph
22
Original post by TenOfThem
No

APR is not a similar triangle

It has one common angle ... And one pair of proportional sides



It could only be similar if APR were right angled and we have established that it is not

Sorry:facepalm: I missed that AP=PR
but as APR shares that angle with ABC would it not be fair to say that the scale factor between AB and AC would be the same as that between AP and AR.
(edited 9 years ago)

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