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Maths, mechanics homework!!

Can someone help please?

A particle A of mass 5kg rests on a rough plane inclined at 30 degrees to the horizontal. A string attached to A lies along a line of greatest slope of the plane and passed over a smooth pulley at the top of the plane. A particle B of mass 6kg hangs vertically from the string 1m above a horizontal plane. The system is released from rest with the string taut. If B takes 2 seconds to reach the horizontal plane, find the coefficient of friction between A and the inclined plane. Find also the total distance that A moves up the plane, assuming A does not reach the pulley ?

THANKYOU FOR ANY HELP!!
Original post by Sykesy1
Can someone help please?

A particle A of mass 5kg rests on a rough plane inclined at 30 degrees to the horizontal. A string attached to A lies along a line of greatest slope of the plane and passed over a smooth pulley at the top of the plane. A particle B of mass 6kg hangs vertically from the string 1m above a horizontal plane. The system is released from rest with the string taut. If B takes 2 seconds to reach the horizontal plane, find the coefficient of friction between A and the inclined plane. Find also the total distance that A moves up the plane, assuming A does not reach the pulley ?

THANKYOU FOR ANY HELP!!


Start by drawing a diagram and then resolve vertically using F=ma at B.
Reply 2
Okay but how do you find the coefficient and get rid of the tensions
Original post by Sykesy1
Okay but how do you find the coefficient and get rid of the tensions

What can you find from resolving vertically using F=ma at B?
Reply 4
6g-t=6a
Original post by Sykesy1
6g-t=6a


You can work out what the tension is from here. Use the fact that the particle B travelled 1m in 2 seconds to calculate the acceleration.
Reply 6
Okay do I use a suvat equation to find the acceleration then?
Original post by Sykesy1
Okay do I use a suvat equation to find the acceleration then?


Yes.

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