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How do people fail to answer even ONE question on a BMO1 paper?

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Original post by Krollo

Yes I completely agree :smile:
Don't forget binomial expansion lol otherwise it will take a long time to expand :tongue:
yh the arithmetic is ghastly so people really would have to check quite a few times over.
Original post by MathMeister
Yes I completely agree :smile:
Don't forget binomial expansion lol otherwise it will take a long time to expand :tongue:
yh the arithmetic is ghastly so people really would have to check quite a few times over.

Spoiler

Original post by Mathbomb

Spoiler



Let n=2007 or somethig. Works out mch easier.


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Original post by physicsmaths
Let n=2007 or somethig. Works out mch easier.
Posted from TSR Mobile

That's what I did.
It strangely turns out the quotient is the same as the thing your dividing by.
They do like to make lovely questions :tongue:
it's quite hard to see this with the numbers
In fact the 0.5*(denominator)^2=numerator
so 2*numerator= denominator^2
(edited 9 years ago)
Reply 44
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HLN_Radium
OP
5
Original post by physicsmaths
You got q3 wrong, don't embarrass yourself and close this. The answer is n=11.


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Its 21 lol wtf troll.

Think about it
1+2+3 = 6
Therefore you cannot ever let 1, 2, 3 and 6 ever be in the same group together.

Now, consider the smallest integer in a potential group for a + b + c = d
The smallest integer that is REQUIRED 100% needed to make a group is 1 for values of n between 6 and 8, 2 for 9 to 11 (2+3+4=9), 3 for 12 to 14, 4 for 15 to 17, 5 for 18 to 20, and you can make a set of 21 with 6+7+8.
For 11 (an all n<21) all you have to do is split one group up so that it has the numbers 1-5 and the other group has no chance of making a set.
Reply 45
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HLN_Radium
OP
5
lmfao 11 is the answer that's bullsh*t
Original post by HLN_Radium

For 11 (an all n<21) all you have to do is split one group up so that it has the numbers 1-5 and the other group has no chance of making a set.


1+1+1=3
Reply 47
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HLN_Radium
OP
5
Original post by james22
1+1+1=3

yeah but you used 1 three times. You need to use 2 and 3 as your next smallest numbers.
Original post by HLN_Radium
yeah but you used 1 three times. You need to use 2 and 3 as your next smallest numbers.


Read the question again lol.
Reply 49
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HLN_Radium
OP
5
Original post by james22
Read the question again lol.

no u
Original post by HLN_Radium
no u


Let x=y=z=1 and ;et w=3, what is wrong with this? Nothings says they have to be distinct (it actually clarifies that they don't).
Reply 51
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HLN_Radium
OP
5
Original post by james22
Let x=y=z=1 and ;et w=3, what is wrong with this? Nothings says they have to be distinct (it actually clarifies that they don't).

it said x y z not any combination of x x and x or z y y
Original post by HLN_Radium
it said x y z not any combination of x x and x or z y y


It clearly says they don't need to be distinct.
Reply 53
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HLN_Radium
OP
5
Original post by james22
I clearly said they don't need to be distinct.

ftfy
just cuz u said it doesnt mean the question said it
Original post by HLN_Radium
ftfy
just cuz u said it doesnt mean the question said it


Determine the least natural number
n
for which the following
result holds:
No matter how the elements of the set
{
1
,
2
, . . . , n
}
are coloured red
or blue, there are integers
x, y, z, w
in the set (not necessarily distinct)
of the same colour such that
x
+
y
+
z
=
w

Read the bit in bold.
Reply 55
Avatar for HLN_Radium
HLN_Radium
OP
5
Original post by james22
Determine the least natural number
n
for which the following
result holds:
No matter how the elements of the set
{
1
,
2
, . . . , n
}
are coloured red
or blue, there are integers
x, y, z, w
in the set (not necessarily distinct)
of the same colour such that
x
+
y
+
z
=
w

Read the bit in bold.

lol making stuff up and adding it to the question k.
i know what I read when I read the question
Original post by physicsmaths
Let n=2007 or somethig. Works out mch easier.

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??? That is the answer once you are left with the arithmetic. To get to that I used that method though :P
Original post by HLN_Radium
lol making stuff up and adding it to the question k.
i know what I read when I read the question

i made an account just to downvote you
where's the downvote button
just read through the posts. You guys got baited by OP; I think the trolls win this one.
Original post by james22
...

I struggle to understand the question lol
what have colours got to do with it?
plz explain :tongue:

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