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FP3 Hyperbolic Functions (edexcel)

Hi all,

I can't get my answer into the form they've got it in even though it has the same value. Solution attached.

Would I get marked down for this in an exam?
IMG_1726.jpg504.8KB
Reply 1
Avatar for TeeEm
TeeEm
19
Original post by WatermelonJuice1
Hi all,

I can't get my answer into the form they've got it in even though it has the same value. Solution attached.

Would I get marked down for this in an exam?


you should not lose marks

can you see how to switch between these 2 answers?
Original post by TeeEm
you should not lose marks

can you see how to switch between these 2 answers?


Nope, not really :/
Original post by WatermelonJuice1
Hi all,

I can't get my answer into the form they've got it in even though it has the same value. Solution attached.

Would I get marked down for this in an exam?


That's fine. You might be interested in exploring surd denesting however. If you send me a private message I will send you a short article I wrote about this.
Original post by WatermelonJuice1
Hi all,

I can't get my answer into the form they've got it in even though it has the same value. Solution attached.

Would I get marked down for this in an exam?

Lucky you doing FP3 <3
You're in year 13? Which module do you think has helped you the most in FP3?
Reply 5
Avatar for SH0405
SH0405
15
Original post by WatermelonJuice1
Hi all,

I can't get my answer into the form they've got it in even though it has the same value. Solution attached.

Would I get marked down for this in an exam?


It's difficult to work through to their form from where you are, but if you use the fact, that kln(m) = ln(m^k), it's a bit easier to see. As for whether you'd get marked down, I think you would if they explicitly asked for a particular form.
(edited 9 years ago)
Original post by Placeboo123
Lucky you doing FP3 <3
You're in year 13? Which module do you think has helped you the most in FP3?


I just started it last week so I can't really judge very accurately. So far I'd say FP2.
Reply 7
Avatar for TeeEm
TeeEm
19
Original post by WatermelonJuice1
Nope, not really :/


1/2ln(3+2√2)

=ln[√(3+2√2)]

=ln[12 +2x1x√2+(√2)2]

=ln[√(1+√2)2]

=ln[1+√2]
Original post by TeeEm
1/2ln(3+2√2)

=ln[√(3+2√2)]

=ln[12 +2x1x√2+(√2)2]

=ln[√(1+√2)2]

=ln[1+√2]


You lost me on the 3rd line, but I'm reading into a surd denesting article Mr M sent me so hopefully it will make sense soon.

EDIT: Just read your response again and I get it. Thank you.
(edited 9 years ago)
Reply 9
Avatar for TeeEm
TeeEm
19
Original post by WatermelonJuice1
You lost me on the 3rd line, but I'm reading into a surd denesting article Mr M sent me so hopefully it will make sense soon.


I am using (a+b)2 = a2 +2ab+b2

I hope it makes sense one way or another.

good luck

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