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I'm struggling with: 2^x * 4^x+1 = 8

So far I did 2^x * (2^2)^x+1 = 8 so
2^x * 2^2x+2 = 8

But I don't know if this is right, or what to do next.

Thanks!
Reply 1
Avatar for TeeEm
TeeEm
19
Original post by Qaiys
I'm struggling with: 2^x * 4^x+1 = 8

So far I did 2^x * (2^2)^x+1 = 8 so
2^x * 2^2x+2 = 8

But I don't know if this is right, or what to do next.

Thanks!


you got it so far and you do not know what to do next?
Reply 2
Avatar for Hsakbo
Hsakbo
1
Use parenthesis like (2^x)*((4)^(x+1)) =8

So it should be like this:
2^x * 2^(2x+2) = 2^3
2^(x+2x+2) =2^3
Since bases are.......
3x+2=3
There..
Reply 3
Avatar for white_o
white_o
OP
17
Original post by TeeEm
you got it so far and you do not know what to do next?

Ahh okay, change the 8.

Original post by Hsakbo
Use parenthesis like (2^x)*((4)^(x+1)) =8

So it should be like this:
2^x * 2^(2x+2) = 2^3
2^(x+2x+2) =2^3
Since bases are.......
3x+2=3
There..


Ohhh thanks! :smile:
Reply 4
Avatar for TeeEm
TeeEm
19
Original post by Qaiys
Ahh okay, change the 8.



Ohhh thanks! :smile:




no worries

Hsakbo gave you everything except the answer.

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