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Help on a maths question

Hi guys, it would be great if you guys could help me answer this question.
thanks.

(edited 9 years ago)

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Reply 1
Original post by Chittesh14
Hi guys, it would be great if you guys could help me answer this question.
thanks.

Attachment not found


I am sure somebody will help you but your attachment is invalid
Reply 2
Original post by TeeEm
I am sure somebody will help you but your attachment is invalid



Sorry bro, don't know what the problem was, still works fine for me. But re-uploaded onto this post.
Reply 3
Original post by Chittesh14
Hi guys, it would be great if you guys could help me answer this question.
thanks.



That's not a question - that's just an expression!

Are you being asked to simplify what's written? There are several ways of going about this - one way is to start by writing what's inside the brackets as a power of some fraction. Can you do that?
Reply 4
Original post by davros
That's not a question - that's just an expression!

Are you being asked to simplify what's written? There are several ways of going about this - one way is to start by writing what's inside the brackets as a power of some fraction. Can you do that?


Yeah, sorry I kept doing it wrong lol. I was doing something else like doing 1/4 to the power of -2 and then writing a after it. But, my brother solved it for me and it is correct. I was meant to simplify it and I got the answer as 16a^4.
Reply 5
Original post by Chittesh14
Yeah, sorry I kept doing it wrong lol. I was doing something else like doing 1/4 to the power of -2 and then writing a after it. But, my brother solved it for me and it is correct. I was meant to simplify it and I got the answer as 16a^4.


Your brother was wrong if you're saying he got 16a416a^4
(edited 9 years ago)
Reply 6
Original post by Phichi
Your brother was wrong if you're saying he got 16a416a^4


How, that's the correct answer?
Original post by Chittesh14
How, that's the correct answer?


No its not. Rewrite the middle part.


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Reply 8
Original post by Chittesh14
How, that's the correct answer?


It's not the same as what you wrote down in the first post!

Can you give us a screenshot or photo of the original question?
Reply 9
Original post by davros
It's not the same as what you wrote down in the first post!

Can you give us a screenshot or photo of the original question?


I don't know sorry my friend just needed help on the question and that's all he sent me. Therefore, I just worked out what's in the bracket and then raised it to the power of -3/4 and it face me 16a^4.


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Original post by Chittesh14
I don't know sorry my friend just needed help on the question and that's all he sent me. Therefore, I just worked out what's in the bracket and then raised it to the power of -3/4 and it face me 16a^4.


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But it doesn't give you that

Even if you just consider the fraction (1/4)^-3/4 = 2root2 not 16
Original post by TenOfThem
But it doesn't give you that

Even if you just consider the fraction (1/4)^-3/4 = 2root2 not 16


Yeah, can u explain to me how you got there. I don't really know how to solve this question, my brother got something like that before and then he done it again to get 16a4.


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Original post by Chittesh14
Yeah, can u explain to me how you got there. I don't really know how to solve this question, my brother got something like that before and then he done it again to get 16a4.


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The negative power means reciprocal giving 4

The 1/4 power means fourth root giving root2

The 3 power means cube giving 2root2


No sign of 16
Original post by Chittesh14
Yeah, can u explain to me how you got there. I don't really know how to solve this question, my brother got something like that before and then he done it again to get 16a4.


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So u have 1/(1/4)^3/4 yes
Square root to give 1/(1/2)^3/2
Repeat again to give 1/(1/root2)^3
Which will give the answer


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Original post by TenOfThem
The negative power means reciprocal giving 4

The 1/4 power means fourth root giving root2

The 3 power means cube giving 2root2


No sign of 16


Original post by physicsmaths
So u have 1/(1/4)^3/4 yes
Square root to give 1/(1/2)^3/2
Repeat again to give 1/(1/root2)^3
Which will give the answer


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Oh right thanks guys, that's exactly what my brother done and got the answer 2 root 2. But, what happened to the a? Where does the letter a go.


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Original post by Chittesh14
Oh right thanks guys, that's exactly what my brother done and got the answer 2 root 2. But, what happened to the a? Where does the letter a go.


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Oh yh put that in there a^3/2


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Original post by physicsmaths
Oh yh put that in there a^3/2


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So, should the answer be 2 root 2, where is the a? lol.
It's like root 2 multiplied by a and then to the power of 3? is that what your saying.
Original post by Chittesh14
So, should the answer be 2 root 2, where is the a? lol.
It's like root 2 multiplied by a and then to the power of 3? is that what your saying.


Look we have done (1/4)^-3/4
No multiply it by (a^-2)^-3/4
If you use indices you should find that part extremely easy.


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Original post by physicsmaths
Look we have done (1/4)^-3/4
No multiply it by (a^-2)^-3/4
If you use indices you should find that part extremely easy.


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(a^-2)^-3/4 =
a^-2 = 1/a^2 then
(1/a^2)^-3/4 = 1 / (1/a^2)^3/4 =
(a^2)^3/4 = fourth root of a^2 = square root of a^2 = a, square root of a = root a.
cube root a = a root a?

So the answer should be 2 root 2 and a root a? im confused lol.
Original post by Chittesh14
(a^-2)^-3/4 =
a^-2 = 1/a^2 then
(1/a^2)^-3/4 = 1 / (1/a^2)^3/4 =
(a^2)^3/4 = fourth root of a^2 = square root of a^2 = a, square root of a = root a.
cube root a = a root a?

So the answer should be 2 root 2 and a root a? im confused lol.


Yes but u couldve just done -2x-3/4=3/2 so a^3/2 but yh thats aroota.


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