The equilibrium below was established by allowing 2 moles of ethanol and 1 mole of ethanoic acid to react at 25 degrees Celsius. At equilibrium the mixture contained 0.845 moles of ethyl ethanoate. Calculate Kc at this temperature.
CH3COOH + CH3CH2OH -> CH3COOCH2CH3 + H2O
So obviously work out Kc. But then can I just sub the values of the moles in since no volume was given or do I need to work out the Mr etc.