AQA Physics PHYA4 - Thursday 11th June 2015 [Exam Discussion Thread]

OP

Original post by susanjan123

Hey guys, anyone doing UNIT6 ISA? And if so any idea what it's on?? I'm a external student resitting mine so I have MINIMUM idea what it is on :frown:

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Same question but for the EMPA hahha.

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Reply 122

SmartIndianMan

12

Original post by susanjan123

Hey guys, anyone doing UNIT6 ISA? And if so any idea what it's on?? I'm a external student resitting mine so I have MINIMUM idea what it is on :frown:

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I'm doing my first practical on 26th Feb, but dunno what's it on. What date r u doin it on?

Reply 123

susanjan123

5

I haven't been told a date yet, mine is on capacitors :|

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Reply 124

OP

Original post by susanjan123

I haven't been told a date yet, mine is on capacitors :|

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I had a mock EMPA on that the other week aha.

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Reply 125

Screen Shot 2015-02-10 at 18.24.28.png24.2KB

Reply 126

Original post by KeithHayward

Jeez. I'm going to go with D.

Reply 127

OP

Original post by KeithHayward

Isn't it A?

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Reply 128

Original post by CD223

Isn't it A?

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What's your reasoning?

Reply 129

Original post by JaySP

Jeez. I'm going to go with D.

Original post by CD223

Isn't it A?

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The answer is B (june 2009). What's the reasoning behind both of your answers? Im stumped?

Reply 130

Original post by KeithHayward

The answer is B (june 2009). What's the reasoning behind both of your answers? Im stumped?

My reasoning:
If l, length, is smaller, the time period T will as a result be smaller. If T is smaller, the acceleration will be larger. Since acceleration is proportional to displacement from equilibrium, if acceleration is larger, the amplitude will be larger.

Are you sure its June 09? just tried to find the examiners report but no Unit 4 paper was released that cycle?

(edited 9 years ago)

Reply 131

Original post by JaySP

My reasoning:
If l, length, is smaller, the time period T will as a result be smaller. If T is smaller, the acceleration will be larger. Since acceleration is proportional to displacement from equilibrium, if acceleration is larger, the amplitude will be larger.

Are you sure its June 09? just tried to find the examiners report but no Unit 4 paper was released that cycle?

I'm sure (https://www.school-portal.co.uk/GroupDownloadFile.asp?GroupId=13924&ResourceId=2727216). That was my reasoning too. If you know how to, do you mind @ing 'stonebridge'?

Reply 132

Original post by KeithHayward

I'm sure (https://www.school-portal.co.uk/GroupDownloadFile.asp?GroupId=13924&ResourceId=2727216). That was my reasoning too. If you know how to, do you mind @ing 'stonebridge'?

Can't find the examiner's report anywhere. :confused:

and I don't know how to @ someone on TSR, sorry :confused:

Reply 133

dannywaughman

1

Is it to do with resonance and the natural frequency being similar?

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Reply 134

Original post by dannywaughman

Is it to do with resonance and the natural frequency being similar?

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Doons

Reply 135

Original post by dannywaughman

Is it to do with resonance and the natural frequency being similar?

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Original post by JaySP

Doons

Is this right? If so how do you know that the nat freqs are similar?

Reply 136

Original post by KeithHayward

Is this right? If so how do you know that the nat freqs are similar?

I think Danny and I concluded:
Something about the length of strings being related to the frequency of oscillation
Something about the frequency of P being the Natural Frequency
Something about the closer the string length to P, the more vigorous the oscillations of the other mass (ie resonance).

It does make a little sense. if two lengths of a string are the same, they are going to have the same time period, and thus similiar amplitudes. (Or I'm just BS'ing).

(edited 9 years ago)

Reply 137

OP

Original post by KeithHayward

The answer is B (june 2009). What's the reasoning behind both of your answers? Im stumped?

I don't know tbh. I thought as it was longest it had the largest amplitude, but then I realised I got mixed up between the relationship between length and amplitude and length and time period aha. Sorry.

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Reply 138

Original post by dannywaughman

Is it to do with resonance and the natural frequency being similar?

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Original post by JaySP

I think Danny and I concluded:
Something about the length of strings being related to the frequency of oscillation
Something about the frequency of P being the Natural Frequency
Something about the closer the string length to P, the more vigorous the oscillations of the other mass (ie resonance).

It does make a little sense. if two lengths of a string are the same, they are going to have the same time period, and thus similiar amplitudes. (Or I'm just BS'ing).

Original post by CD223

I don't know tbh. I thought as it was longest it had the largest amplitude, but then I realised I got mixed up between the relationship between length and amplitude and length and time period aha. Sorry.

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It makes quite a bit of sense, but I don't know if we're missing something. To save us teaching ourselves the wrong thing i'll ask my teacher tomorrow and see what he says...

CD223 I did the same earlier :frown:

Will keep you all updated if nothing else emerges in the meantime

Reply 139

OP