Original post by Vidsify
I'm unsure on this question
a) Expand (1+4/x)^2
Would you treat the 4/x as 4/1 or what?
Thanks in advance
a) Expand (1+4/x)^2
Would you treat the 4/x as 4/1 or what?
Thanks in advance
You treat it as
Original post by TenOfThem
You treat it as
Ok so how would I expand it?
Original post by Vidsify
Ok so how would I expand it?
You would put that instead of x
Original post by Vidsify
I'm unsure on this question
a) Expand (1+4/x)^2
Would you treat the 4/x as 4/1 or what?
Thanks in advance
a) Expand (1+4/x)^2
Would you treat the 4/x as 4/1 or what?
Thanks in advance
Because the power is a positive integer you can expand using the (a+b)n formula where a would be one and b would be x/4. Hope that helps.
Original post by Vidsify
Ok so how would I expand it?
The same way you do any other expansion!
If it helps, write 4/x = y and pretend you're expanding (1 + y)^2
Original post by davros
The same way you do any other expansion!
If it helps, write 4/x = y and pretend you're expanding (1 + y)^2
If it helps, write 4/x = y and pretend you're expanding (1 + y)^2
What then at the end swap the y's for the 4/x?
Original post by Vidsify
What then at the end swap the y's for the 4/x?
I'm hoping you would've realised that by now after 4 posts telling you!
Original post by Phichi
I'm hoping you would've realised that by now after 4 posts telling you!
Well it wasn't particularly clear
Original post by Vidsify
Well it wasn't particularly clear
Seriously?
Use the taylor series expansion to expand it, setting f(x) = x^-1 and a=1
Original post by CancerousProblem
Use the taylor series expansion to expand it, setting f(x) = x^-1 and a=1
Clearly if he is asking a question on binomial expansion, I doubt he's really looking to taylor expand it, I doubt OP even knows about the taylor series, let alone can execute it, why post this?
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