A 5g iron ball at 95°C is added to a well-insulated beaker containing 10g of water and allowed to thermally equilibrate, reaching a temperature of 45°C.
Cp(Iron)=25.1JK-1mol-1
Cp(water)=75.3JK-1mol-1
What was the original temperature of the water?
i assume i have to use the q=m*c*deltaT equation but i dont know how to use it