AS Chemistry- helping each other out!
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Original post by C0balt
Aqa
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Original post by samb1234
Btw we don't do coulombs law I just happen to know it
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Original post by TeaAndTextbooks
Thanks alot I get it now
Glad to be of help
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Original post by samb1234
Yeah I was like "were we examined in the law???"
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Original post by C0balt
You learn a lot of random stuff when one of your best friends read the entire Feynman lectures
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Original post by C0balt
Never come across that lol only HX I have seen was halides in my AS course
Now I won't randomly assume in my exams, great
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Now I won't randomly assume in my exams, great
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Yeah it's really common in Scotland, but the giveaway in that question was " ... the acid HX".
Original post by Hype en Ecosse
Yeah it's really common in Scotland, but the giveaway in that question was " ... the acid HX".
Yea said acid so just assumed carboxylic
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Original post by samb1234
You learn a lot of random stuff when one of your best friends read the entire Feynman lectures
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I'd read about the law before but didn't quite get the equation so I kinda got scared when you mentioned it lol
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Original post by C0balt
I'd read about the law before but didn't quite get the equation so I kinda got scared when you mentioned it lol
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The only bit that is useful really is the fact that it means that the attraction is inversely proportional to r^2
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Original post by samb1234
The only bit that is useful really is the fact that it means that the attraction is inversely proportional to r^2
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As far as chemistry goes anyway
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Original post by samb1234
Ah so further apart the electron the less attraction there is so less ionisation energy and all that argument
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Original post by C0balt
Ah so further apart the electron the less attraction there is so less ionisation energy and all that argument
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Yep
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Original post by samb1234
Thanks for the new knowledge
I really love knowing the connection between chemistry and physics, which is why I'm applying for Chemical Physics
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What would you guys say the biggest source of your potential errors are when performing titrations?
Perhaps using a pipette and not getting the meniscus on the line! ?
How much of a difference could this possibly make....
Perhaps using a pipette and not getting the meniscus on the line! ?
How much of a difference could this possibly make....
Original post by wednesday_adams
What would you guys say the biggest source of your potential errors are when performing titrations?
Perhaps using a pipette and not getting the meniscus on the line! ?
How much of a difference could this possibly make....
Perhaps using a pipette and not getting the meniscus on the line! ?
How much of a difference could this possibly make....
I'd say probably the biggest source of error is the human error of stopping exactly at the end point. It's very east to go past the endpoint. The meniscus and pipette do have an effect though as well
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Hi does anyone know the group 2 compound which is insoluble in water and gives of co2 and White sold when reacted with sulfuric acid?
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How would I calaculate this; concentration of NAOH was 0.100 moldm^-3, where the average titre is X to work the amount in moles of HCL in a volumentric flask..? Looking for calc
Original post by Nidfeo
Do you know the volume of the flask?
250 cm^3
Original post by Uwaiss
How would I calaculate this; concentration of NAOH was 0.100 moldm^-3, where the average titre is X to work the amount in moles of HCL in a volumentric flask..? Looking for calc
Mol=conc x vol
Conc is 0.1 and volume is X. Put X in dm3 by dividing by 1000.
Mol=0.1 x (X in dm3)
That is moles of NaOH. Since it's 1:1 ratio the moles of NaOH equals moles HCl.
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(edited 9 years ago)
Original post by Dylann
Mol=conc/vol
Conc is 0.1 and volume is X. Put X in dm3 by dividing by 1000.
Mol=0.1/(X in dm3)
That is moles of NaOH. Since it's 1:1 ratio the moles of NaOH equals moles HCl.
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Conc is 0.1 and volume is X. Put X in dm3 by dividing by 1000.
Mol=0.1/(X in dm3)
That is moles of NaOH. Since it's 1:1 ratio the moles of NaOH equals moles HCl.
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My average titre if I was reckon was 30.9 would the calc be.. 0.1 / 0.0309? which is 3.09x10^-3?
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