The Student Room Group

AS Chemistry- helping each other out!

Scroll to see replies

Original post by samb1234

Oh sorry this one.
Original post by Kadak
Oh sorry this one.


Close but a slight mistake I think

Posted from TSR Mobile
Original post by Kadak
Oh sorry this one.


Sign

Posted from TSR Mobile


For reaction it's products - reactants

Combustion it is CRaP
Reactants - Products

Posted from TSR Mobile
Original post by C0balt
For reaction it's products - reactants

Combustion it is CRaP
Reactants - Products

Posted from TSR Mobile


Oh Ty! I find it odd a formation reaction is exothermic.
Original post by Kadak
Oh Ty! I find it odd a formation reaction is exothermic.

Bond forming is always exothermic.
Bond breaking is endothermic.
That's a general rule you have to know.

Posted from TSR Mobile
Reply 1767
Original post by TheGreatImposter
Of course. I got a U in my first chemistry test and now I'm averaging As. Just gotta understand the content, go over it regularly and do past papers. I usually watch YouTube videos on the topics I find difficult and that helps.

Posted from TSR Mobile


Thank your your advise will definitely do that
Reply 1768
Original post by Disney0702
Hi there!

I am an A2 Chemistry student.

I got an A last year at AS level.

In the March MOCKs I got a U grade for Chemistry but that was because I lacked understanding at that time.

To help me understand better I bought the CGP text book which helped contribute to my A grade.

I recommend you get it if you really want that high A grade.

CGP AS Chemistry

SAMPLE PAGES

I also recommend you do lots of past papers so help strengthen your exam technique.


Thank you so much
I have that book
And I will start to use it more wisely
I really appreciate your reply :smile:
Can somebody help me please?
When testing for a sulfate ion, you add BaCl2 to form a white precipitate. If no sulfate ion is present, what is the observation? Does the solution stay clear or can a different coloured precipitate form?
Original post by prophetkid
Can somebody help me please?
When testing for a sulfate ion, you add BaCl2 to form a white precipitate. If no sulfate ion is present, what is the observation? Does the solution stay clear or can a different coloured precipitate form?

the solution stays colourless.
All group 2 compound form white precipitate
Only transition metals form coloured ones (dichromate, permagnate have colours but they are transition metal anion)
Original post by C0balt
the solution stays colourless.
All group 2 compound form white precipitate
Only transition metals form coloured ones (dichromate, permagnate have colours but they are transition metal anion)


Thank you! Do you know which transition metals would form a blue precipitate?
Original post by prophetkid
Thank you! Do you know which transition metals would form a blue precipitate?


Cu2+ ion is blue

Posted from TSR Mobile
Reply 1773
How do I work out;

mass of MG(OH)2 that may have been used in the medicine.

Mass = molesxmr
mass = moles x 58.3

Info given is; hcl moles is 20.4 x 10^-3
The amount of acid which was used was 50cm^3 and concentration was 1moldm^3

(may need to work the hydroxide ions or something along them lines?)
Original post by Uwaiss
How do I work out;

mass of MG(OH)2 that may have been used in the medicine.

Mass = molesxmr
mass = moles x 58.3

Info given is; hcl moles is 20.4 x 10^-3
The amount of acid which was used was 50cm^3 and concentration was 1moldm^3

(may need to work the hydroxide ions or something along them lines?)


Write out the balanced chemical equation for the reaction and then you can work out the mole ratio

Posted from TSR Mobile
Hey!
Can you please tell me how do you do this?
It would be great help!
Thanks a lot:smile:

The answer is C btw but idk how!
Reply 1776
Original post by samb1234
Write out the balanced chemical equation for the reaction and then you can work out the mole ratio

Posted from TSR Mobile


Mg(OH)2 + 2HCL -> MgCl2 + 2H20

2:1 ratio now what dude
Original post by Uwaiss
How do I work out;

mass of MG(OH)2 that may have been used in the medicine.

Mass = molesxmr
mass = moles x 58.3

Info given is; hcl moles is 20.4 x 10^-3
The amount of acid which was used was 50cm^3 and concentration was 1moldm^3

(may need to work the hydroxide ions or something along them lines?)

ratio 1:2 because
Mg(OH)2+2HCl -> H2O+MgCl2

So number of moles of Mg(OH)2 is half that of HCl

Multiply it by the Molar mass of Mg(OH)2 and that's the mass of Mg(OH)2
(edited 9 years ago)
Original post by C0balt
ratio 1:2 because
Mg(OH)2+2HCl -> H2O+MgCl2

So number of moles of Mg(OH)2 is half that of HCl

Multiply it by the Molar mass of Mg(OH)2 and that's the mass of Mg(OH)2

and about that ion thing, it's a separate question
if you want the number of moles of OH- ions that is double the number of moles of Mg(OH)2 because there are 2 OH- in one Mg(OH)2
Ok hi, I recently asked about carrying forward answers rounded or unrounded
can any one else doing aqa confirm that this format is acceptable

a) X/n = 2.46728478
= 2.47 (3sf)
Part b depends on part a

b) m = (2.467...)(5)
= 12.33572814684 (not actual value)
=12.3 (3sf)

Quick Reply

Latest