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help needed with math question

hey could anyone help me with this??

Images:maths uni.pngScreen Shot 2015-05-11 at 17.06.31.png
(edited 8 years ago)

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Post the math question?
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gandanmo2
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Original post by Marshall Taylor
Post the math question?


im trying god its hard first time posting an image ;'D
(edited 8 years ago)
Still can't see it? Would it be possible to write out?
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Original post by footchemllab
Still can't see it? Would it be possible to write out?


ive done it now :biggrin:
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gandanmo2
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Original post by Marshall Taylor
Post the math question?


Here ya go XD
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gandanmo2
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i know its complex numbers but still i cant figure it out haha ive been out of the maths game for a year.. :'(
I didn't do maths at uni so I might be wrong! For the first part, can't you multiply it by (1+i(rt3))/(1+i(rt3)) to get 1/4 + ((rt3)/4)i

Sorry if that's not much help!
Then from there, we use Euler's formula as illustrated in this link http://www.mathsisfun.com/algebra/eulers-formula.html

We can then convert 1/4 + (rt3)/4 i into polar coordinaties, like re^io

So r would be rt( (1/4)^2 + ((rt3)/4)^2) which is 1/2.

Theta is tan^-1( rt3/4)/(1/4) which is exactly 60 degrees, so in radians is 1/3 pi radians.

So it would be 1/2 e^1/3 *pi*theta
Original post by gandanmo2
i know its complex numbers but still i cant figure it out haha ive been out of the maths game for a year.. :'(

Just realised I didn't quote you :tongue:, does my explanation look right/make sense?
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Original post by footchemllab
I didn't do maths at uni so I might be wrong! For the first part, can't you multiply it by (1+i(rt3))/(1+i(rt3)) to get 1/4 + ((rt3)/4)i

Sorry if that's not much help!


im sucha numpty i just refreshed the page i thought this was twitter automatically refreshing

why would you times it by (1+i(rt3))/(1+i(rt3)??
Original post by gandanmo2
im sucha numpty i just refreshed the page i thought this was twitter automatically refreshing

why would you times it by (1+i(rt3))/(1+i(rt3)??


No problem :smile:

Basically, it allows us to remove the imaginary number from the denominator. We're effectively multiplying by 1 but making our equation more simplistic in doing so, allowing us to put it in the form required.
Original post by gandanmo2
im sucha numpty i just refreshed the page i thought this was twitter automatically refreshing

why would you times it by (1+i(rt3))/(1+i(rt3)??


maths.jpg
Reply 13
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gandanmo2
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Original post by footchemllab
No problem :smile:

Basically, it allows us to remove the imaginary number from the denominator. We're effectively multiplying by 1 but making our equation more simplistic in doing so, allowing us to put it in the form required.


would (1+i(rt3)) x the denominator (1-i(rt3)) and cancelling out to give us 1+ i^2 root3?
Original post by gandanmo2
would (1+i(rt3)) x the denominator (1-i(rt3)) and cancelling out to give us 1+ i^2 root3?


Can you see the pic I attached above? I wrote it down on there, if you can read my pretty appalling writing :tongue:
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Original post by footchemllab
Can you see the pic I attached above? I wrote it down on there, if you can read my pretty appalling writing :tongue:


Oh got it! yeah you utter badass! thanks bro! any help with part B (not A2) :biggrin:
Original post by gandanmo2
Oh got it! yeah you utter badass! thanks bro! any help with part B (not A2) :biggrin:


No problem :smile: I can't see a part B though?
Reply 17
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Original post by footchemllab
No problem :smile: I can't see a part B though?


crap. my bad i meant part 2
Original post by gandanmo2
crap. my bad i meant part 2


I'm not a fan of proofs so this video can explain it better than me :smile:

https://www.youtube.com/watch?v=oNKfW8Am36M
Reply 19
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gandanmo2
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Original post by footchemllab
I'm not a fan of proofs so this video can explain it better than me :smile:

https://www.youtube.com/watch?v=oNKfW8Am36M


thanks so much :biggrin:
honestly means alot!

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