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OCR (not MEI) C1 - Wednesday 13th May 2015

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Original post by rich1334
I put 6x-8y-29 I think


Yeh that was it :smile:) I put that too
Original post by micycle
Were the simultaneous equations:

2x+y=5 AND x^2-y^2=3

OR

2x+y=5 AND x^2+y^2=3


first one!!!
Original post by micycle
Were the simultaneous equations:

2x+y=5 AND x^2-y^2=3

OR

2x+y=5 AND x^2+y^2=3


The first one
Original post by User10102929
Got -1/48 for this I think


Grrr

Anyone know how many marks this was out of?
Pretty sure it is this
image.jpg319.8KB
Original post by micycle
Were the simultaneous equations:

2x+y=5 AND x^2-y^2=3

OR

2x+y=5 AND x^2+y^2=3


2x+y=5 AND x^2-y^2=3
Original post by Sayersss
Grade boundary expectations?

Was an easy paper but subject to a fair few mistakes

My estimate is around 65/66, same as last year


I'd say the one last year was a lot easier. I'm hoping for 62/63.
Original post by Brian luiz
I got both of those answers, im sure they are right.


I got both of these too
Reply 128
Avatar for dh97
dh97
1
can someone please do an unofficial mark scheme for this paper???/

and how is A=13????
Original post by AstroNandos
Grrr

Anyone know how many marks this was out of?



pretty sure it was 4
Original post by Parallex
was that find the gradient of x1/3x^{1/3} when x=8?

I got -1/48 for that



Was it not -1/3?
So for part 2iii is stretch 1/3 parallel to y wrong??
Original post by Parallex
pretty sure it was 4


Oh. ****. :frown:
Original post by lily9666768
first one!!!


In which case, the simultaneous equation:


= 2 & 14/3
Original post by Dentist214
That gives me hope, would they need to be high A's in c2 and s1 like 65/72? Obviously depending on grade boundaries but never seen them higher than that


65/72 was unusually high for a core 1 exam. They're normally 61/62 and s1 and core 2 A marks are normally 56-59
A will be 66
Original post by AstroNandos
Was it not -1/3?



yeah it was my bad!

solution:

f(x)=x−1/3[br]f′(x)=(−1/3)x−4/3[br]f′(8)=(−1/3)8−4/3[br][br]8−4/3=1/16[br][br](−1/3)(1/16)=−(1/48)[br]f(x) = x^{-1/3}[br]f'(x) = (-1/3)x^{-4/3}[br]f'(8) = (-1/3)8^{-4/3}[br][br]8^{-4/3} = 1/16[br][br](-1/3)(1/16) = -(1/48)[br]
Original post by AstroNandos
Was it not -1/3?


Pretty surr i got-16/3 question was definitely x^-1/3

Edit: I was wrong, eugh I've dropped so many stupid marks
(edited 8 years ago)
Original post by Katie.R.S.
So for part 2iii is stretch 1/3 parallel to y wrong??


Yes its stretch of scale factor 1/3 parallel to x axis
Original post by AstroNandos
Was it not -1/3?


Dy/dx = -1/3x^-4/3

Input 8:

-1/3 x 1/16 = -1/48.

Not sure if that's what I put in the exam but looking now it's quite straight forward..

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