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AQA maths core 1, 13th May 2015

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Original post by jas29031997
What did everyone get for r, was it a max or min?


I put down maximum since the equation towards the end of my working out was something like -1/2 pi square root of 48
Original post by asunny1998
How did you get the shortest length as 4? I did Pythagoras for it.
50 + (2)^2= root 54
I might be wrong though


no the shortest length was 7
what question was it about?
Reply 83
Avatar for Sguest16
Sguest16
I got like 33 1/5 for the integration one for the area of shaded region
Unofficial mark scheme yet??
Original post by Hellohello1237
trapezium mate

trapezium = 54

54 - 108/5 = 162/5 or 32.4


i got this too!
I got 162/5 for the integration question
what did everyone get for the translated curve? I got x^2-x+4..?
Reply 87
Avatar for rkoria
rkoria
3
What did everyone get for n?
Anyone know if Mr M would do an unofficial mark scheme?
how about the polynomial question?
1.Sketch the graph x^2(x-3)+20
2.the remainer when x-4(divide)
3.Put it into (x+3)(x^2+bx+c)
4 P(x)=0 Find the root and give the value
Original post by Heffalump .
I got 162/5 for the integration question
what did everyone get for the translated curve? I got x^2-x+4..?


thats what I got
Original post by harrybo6
your right i accidently did 2(root5) squared instead of 5(root2) squared:frown:


Me too 😭
Original post by Hellohello1237
1) -5/3
coordinate A (9, -4)

2) 7+ √15

3) y=-10x -4
108/5
162/5

6) show something
r= 4
second derivative = -12pi so it's a max value

8) -4/9 < k < 4


Dunno what question number
Chord to centre = 7


I got all these too 👍
Original post by Pandameglanda
Me too

lifes a bitch
Reply 94
Avatar for tadit
tadit
2
Original post by Heffalump .
I got 162/5 for the integration question
what did everyone get for the translated curve? I got x^2-x+4..?

Same here :smile:
Original post by Pandameglanda
Me too

lifes a bitch, u think we will get like working out marks? beauce the only thing wrong was putting the 2 and the 5 the wrong way round
FINAL MARKSCHEME:

Question 1
(a) -3/5 [2]
(b)(i)
perp. gradient = 5/3
y-?=5/3(x-?)
5x-3y+1=0 [3]
(b)(ii) A(9,-4) [3]

Question 2
7+√15
n=7 [5]

Question 3
(a) y=-10x-4 [4]
(b)(i) 108/5 (oe, e.g. 21.6) [5]
(b)(ii). 162/5 (oe, e.g. 32.4) [3]

Question 4
(a) (x+1)^2 + (y-3)^2 = 50 [2]
(b)(i). C(-1,3) [1]
(b)(ii) 5√2 [2]
(c)
k^2-6x-16
(k-8)(k+2)
k=8, k=-2 [2]
(d) min. distance = 7 [2]

Question 5
(a) p = 3/2, q = -¼ [3]
(b)(i) (-3/2, -¼) [2]
(b)(ii) line of symmetry is x=-3/2 [1]
(c) y=x^2-x+4 [3]

Question 6
**IT WAS AN OPEN TOP CYLINDER DAMNIT**
(a)(i) h = 24/r -r/2 [3]
(a)(ii) Sub πr^2 into part (i) to get V = 24πr -π/2 r^3 [3]
(b)(i) 24π -3π/2 r^2 [2]
(b)(ii)
r=4 when dy/dx=0
r=4 => d^2y/dx^2(=-12π)<0, therefore maximum [4]

Question 7
(a) http://i.imgur.com/rVJ169A.png [3]
(b)(i) R = 36 [2]
(b)(ii) R= 0 therefore root [2]
(b)(iii)(x-2)(x^2-5x+10) [2]
(b)(iv) x=2 [3]

Question 8
(a) (Show) x^2 + 3(k-2)x -13-k=0 [1]
(b) 9k^2-32k-16<0 [3]
(c) -4/9< k<4 [4]
(edited 8 years ago)
messsed up on question 3,6 polynomails and chord..hmmm
Original post by Heffalump .
I got 162/5 for the integration question
what did everyone get for the translated curve? I got x^2-x+4..?


Yes and yes.
Reply 99
Avatar for tamcat
tamcat
10
Original post by Hellohello1237
trapezium mate

trapezium = 54

54 - 108/5 = 162/5 or 32.4




thank the lord! i got the same!!

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