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OCR MEI - FP1 - 14th May 2015

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Original post by TheMarshan
Are you sure it is z=1, I am almost 100% sure it was just the default equation multiplied through by z.

My calculator saved the equation, Z^3-7Z^2+11Z+123 Went to Z^4-7Z^3+11Z^2+123Z. Which can be factorized to Z(Z^3-7Z^2+11Z+123), so Z = 0, -3, 5+4j and 5-4j.

Correct me if I am wrong :smile:


Me and my mate nabeel got z=1 for part iv mate
Original post by adrianblazesit
lol james cos i do further maths right? also username checks out so you know it isn't me


literally no idea what you mean
Original post by Darcy1
Me and my mate nabeel got z=1 for part iv mate


Ritesh you new age battyplex
Original post by jpetersgill
Ritesh you new age battyplex


tee hee hee XD
Darcy1 can jump over his back door
Original post by Darcy1
Me and my mate nabeel got z=1 for part iv mate

Yeah also got z=1, as if was z(f)=(f) therefore z(f)-(f)= 0

(f) (z-1) = 0 so z=1. But I could be wrong
Original post by alistairBruv
Darcy1 can jump over his back door


lowe the beef youre better than this
zf(z) = f(z)
Answer is z = 1, z = -3, z = 5 - 4j and z = 5 + 4j
Original post by Mathbomb
zf(z) = f(z)
Answer is z = 1, z = -3, z = 5 - 4j and z = 5 + 4j


For the argand diagram question did you represent the argz = 0 and argz = p/4 with dotted lines or does it not matter?
Original post by Darcy1
For the argand diagram question did you represent the argz = 0 and argz = p/4 with dotted lines or does it not matter?


Solid lines, the inequalities weren't strict
Original post by Mathbomb
zf(z) = f(z)
Answer is z = 1, z = -3, z = 5 - 4j and z = 5 + 4j


+1 confirm
Original post by StrangeBanana
Solid lines, the inequalities weren't strict


Well ****

Oh well it was only 2 marks will probs get at least 1
Original post by Darcy1
Well ****

Oh well it was only 2 marks will probs get at least 1


bad luck m8
What did people get as the values of p and r? And the roots to the equation?
Original post by MonteVerdi123
What did people get as the values of p and r? And the roots to the equation?


q = -7
r = 123
roots 5+/-4j -3 and 1
Original post by MonteVerdi123
What did people get as the values of p and r? And the roots to the equation?


roots were defo 5+/-4j and -3 so yeah :P I think r was 123 but you can check that with the 3 roots that are 100% correct :smile:
For the roots q of 8, would I get a mark for dividing the equstion by z+3 as z=-3 was a root?
How much will be 100UMS?
If I wrote a non strict inequality for the graph question near the asymptotes will I loose 1 or 2 marks?
Original post by notebook123
How much will be 100UMS?
If I wrote a non strict inequality for the graph question near the asymptotes will I loose 1 or 2 marks?


Usually just 1 mark unless both of the inequalities required were incorrect. Usually it hovers around 70 for full UMS but either way you should still score extremely highly. Nice job man!
SO worried I won't get 95 UMS now :/ ... Can't believe I read it as +j and no -j despite even writing it out at arg(z-(-1-j)). Oh my stupidity worries me sometimes

What was grade boundaries for 100 UMS , 90 UMS and 80 UMS last few years? Seems to many different ones lool

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