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Mr M's OCR (not OCR MEI) Further Pure 1 Answers May 2015

Mr M's OCR (not OCR MEI) Further Pure 1 Answers May 2015


1. 2(x2+y2)2(x^2+y^2) (3 marks)


2. n2(2n3)(n+3)\frac{n}{2} (2n-3)(n+3) (4 marks)


3. (i) 12(1a02)\frac{1}{2} \begin{pmatrix} 1 & -a \\0 & 2 \end{pmatrix} (2 marks)

(ii) (10212a)\begin{pmatrix} 1 & 0 \\2 & 1-2a \end{pmatrix} (3 marks)


4. Complete proof (5 marks)


5. (i) Circle centre -2 + 0i radius 2 and half line starting at the centre of the circle 30 degrees above the negative real axis (4 marks)

(ii) 23+i-2-\sqrt 3 + i (2 marks)

(iii) Shade sector inside circle between half line and negative real axis (2 marks)


6. (i) A' = (0, -1) B' = (2, -1) C' = (2, 0) (3 marks)

(ii) One possible combination is stretch in y direction scale factor 2

(1002)\begin{pmatrix} 1 & 0 \\0 & 2 \end{pmatrix}

followed by rotation 90 degrees clockwise about the origin

(0110)\begin{pmatrix} 0 & 1 \\-1 & 0 \end{pmatrix} (4 marks)


7. (i) ±(3+2i)\pm (3+2i) (5 marks)

(ii) x=12ix=-1-2i or x=5+2ix=5+2i (5 marks)


8. (i) Show (2 marks)

(ii) 1n+13n+72-\frac{1}{n+1}-\frac{3}{n}+\frac{7}{2} (6 marks)

(iii) 54\frac{5}{4} (2 marks)


9. (i) a = 5 or a = 1 (6 marks)

(ii) (a) Unique solution

(b) Inconsistent equations (4 marks)


10. (i) u3+8u2+16u9=0u^3+8u^2+16u-9=0 (3 marks)

(ii) 29 (7 marks)


Edit: I've corrected the answer to 8(ii) as it had the wrong signs and 3(ii) as it was just wrong
(edited 8 years ago)

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Reply 1
Thanks Mr M. :smile:
Reply 2
Original post by Mr M
Mr M's OCR (not OCR MEI) Further Pure 1 Answers May 2015


1. 2(x2+y2)2(x^2+y^2) (3 marks)


2. n2(2n3)(n+3)\frac{n}{2} (2n-3)(n+3) (4 marks)


3. (i) 12(1a02)\frac{1}{2} \begin{pmatrix} 1 & -a \\0 & 2 \end{pmatrix} (2 marks)

(ii) (12a22a+1)\begin{pmatrix} 1 & 2a \\2 & 2a+1 \end{pmatrix} (3 marks)


4. Complete proof (5 marks)


5. (i) Circle centre -2 + 0i radius 2 and half line starting at the centre of the circle 30 degrees above the negative real axis (4 marks)

(ii) 23+i-2-\sqrt 3 + i (2 marks)

(iii) Shade sector inside circle between half line and negative real axis (2 marks)


6. (i) A' = (0, -1) B' = (2, -1) C' = (2, 0) (3 marks)

(ii) One possible combination is stretch in y direction scale factor 2

(1002)\begin{pmatrix} 1 & 0 \\0 & 2 \end{pmatrix}

followed by rotation 90 degrees clockwise about the origin

(0110)\begin{pmatrix} 0 & 1 \\-1 & 0 \end{pmatrix} (4 marks)


7. (i) ±(3+2i)\pm (3+2i) (5 marks)

(ii) x=12ix=-1-2i or x=5+2ix=5+2i (5 marks)


8. (i) Show (2 marks)

(ii) 1n+1+3n72\frac{1}{n+1}+\frac{3}{n}-\frac{7}{2} (6 marks)

(iii) 54\frac{5}{4} (2 marks)


9. (i) a = 5 or a = 1 (6 marks)

(ii) (a) Unique solution

(b) Inconsistent equations (4 marks)


10. (i) u3+8u2+16u9=0u^3+8u^2+16u-9=0 (3 marks)

(ii) 29 (7 marks)






Firstly thank you Mr M for posting the answers.

For question 8ii on method of differences i could not spot and cancel out the term, how many marks do you think I've lost.
And for 5i i wrote 150° instead of 30°
Thanks again
Original post by Ahmad_18
Firstly thank you Mr M for posting the answers.

For question 8ii on method of differences i could not spot and cancel out the term, how many marks do you think I've lost.
And for 5i i wrote 150° instead of 30°
Thanks again


You have probably lost 3 marks on 8ii.

It is 150 degrees if you measure from the POSITIVE real axis.
Reply 4
Thanks for posting!
Reply 5
What's raw mark is required to gain 100 UMS for June 2013 or June 2012?
Reply 6
For the transformation question, could you do a reflection in the line y=-x followed by a stretch scale factor -2 parallel to the x-axis, because if you multiply those two matrices you get the transformation matrix.
(edited 8 years ago)
Reply 7
Original post by Sahil_
For the transformation question, could you do a reflection in the line y=-x followed by a stretch scale factor -2 parallel to the x-axis, because if you multiply those two matrices you get the transformation matrix.


there's a lot of answers to it
I did rotation 90 degrees clockwise then stretch scale factor 2 parallel to x axis for example

if they get the combined transformation matrix then it's all good
Original post by Mr M
Mr M's OCR (not OCR MEI) Further Pure 1 Answers May 2015


1. 2(x2+y2)2(x^2+y^2) (3 marks)


2. n2(2n3)(n+3)\frac{n}{2} (2n-3)(n+3) (4 marks)


3. (i) 12(1a02)\frac{1}{2} \begin{pmatrix} 1 & -a \\0 & 2 \end{pmatrix} (2 marks)

(ii) (12a22a+1)\begin{pmatrix} 1 & 2a \\2 & 2a+1 \end{pmatrix} (3 marks)


4. Complete proof (5 marks)


5. (i) Circle centre -2 + 0i radius 2 and half line starting at the centre of the circle 30 degrees above the negative real axis (4 marks)

(ii) 23+i-2-\sqrt 3 + i (2 marks)

(iii) Shade sector inside circle between half line and negative real axis (2 marks)


6. (i) A' = (0, -1) B' = (2, -1) C' = (2, 0) (3 marks)

(ii) One possible combination is stretch in y direction scale factor 2

(1002)\begin{pmatrix} 1 & 0 \\0 & 2 \end{pmatrix}

followed by rotation 90 degrees clockwise about the origin

(0110)\begin{pmatrix} 0 & 1 \\-1 & 0 \end{pmatrix} (4 marks)


7. (i) ±(3+2i)\pm (3+2i) (5 marks)

(ii) x=12ix=-1-2i or x=5+2ix=5+2i (5 marks)


8. (i) Show (2 marks)

(ii) 1n+1+3n72\frac{1}{n+1}+\frac{3}{n}-\frac{7}{2} (6 marks)

(iii) 54\frac{5}{4} (2 marks)


9. (i) a = 5 or a = 1 (6 marks)

(ii) (a) Unique solution

(b) Inconsistent equations (4 marks)


10. (i) u3+8u2+16u9=0u^3+8u^2+16u-9=0 (3 marks)

(ii) 29 (7 marks)

Thanks for that. One small thing, would 8ii not give a negative answer for what you had?
Original post by Mr M
I'm not sure what you are asking. The answer to 8ii is correct.


But if you subbed in n=2, you'd get a negative answer :confused:
Original post by Mr M
Mr M's OCR (not OCR MEI) Further Pure 1 Answers May 2015


1. 2(x2+y2)2(x^2+y^2) (3 marks)


2. n2(2n3)(n+3)\frac{n}{2} (2n-3)(n+3) (4 marks)


3. (i) 12(1a02)\frac{1}{2} \begin{pmatrix} 1 & -a \\0 & 2 \end{pmatrix} (2 marks)

(ii) (12a22a+1)\begin{pmatrix} 1 & 2a \\2 & 2a+1 \end{pmatrix} (3 marks)


4. Complete proof (5 marks)


5. (i) Circle centre -2 + 0i radius 2 and half line starting at the centre of the circle 30 degrees above the negative real axis (4 marks)

(ii) 23+i-2-\sqrt 3 + i (2 marks)

(iii) Shade sector inside circle between half line and negative real axis (2 marks)


6. (i) A' = (0, -1) B' = (2, -1) C' = (2, 0) (3 marks)

(ii) One possible combination is stretch in y direction scale factor 2

(1002)\begin{pmatrix} 1 & 0 \\0 & 2 \end{pmatrix}

followed by rotation 90 degrees clockwise about the origin

(0110)\begin{pmatrix} 0 & 1 \\-1 & 0 \end{pmatrix} (4 marks)


7. (i) ±(3+2i)\pm (3+2i) (5 marks)

(ii) x=12ix=-1-2i or x=5+2ix=5+2i (5 marks)


8. (i) Show (2 marks)

(ii) 1n+1+3n72\frac{1}{n+1}+\frac{3}{n}-\frac{7}{2} (6 marks)

(iii) 54\frac{5}{4} (2 marks)


9. (i) a = 5 or a = 1 (6 marks)

(ii) (a) Unique solution

(b) Inconsistent equations (4 marks)


10. (i) u3+8u2+16u9=0u^3+8u^2+16u-9=0 (3 marks)

(ii) 29 (7 marks)


Mr M, for question 5 I mistakenly done the centre of my circle and half line from -2 on the y axis and not on the x axis, My circle went through the origin and I got the half line angle right, how many marks do you think I dropped?
Hi Mr M, thanks for posting.

On the method of differences, i got 5/2 - some terms with n in that i cant remember, but I found a full cancelling pattern and considered integers for r and n-1 and n - how many marks could I pick up for method marks here?
Weirdly I obtained 5/4 for the sum to infinity question with a wrong previous term - would I still gain the marks?
Thanks again
Thank you very much - are you doing the m2 ocr answers by any chance?
Original post by Jamesb17_
But if you subbed in n=2, you'd get a negative answer :confused:


Yes sorry - I used a computer to solve it and must have had a wrong sign somewhere. I've done it by hand and fixed it now.
Original post by jack0997
Hi Mr M, thanks for posting.

On the method of differences, i got 5/2 - some terms with n in that i cant remember, but I found a full cancelling pattern and considered integers for r and n-1 and n - how many marks could I pick up for method marks here?
Weirdly I obtained 5/4 for the sum to infinity question with a wrong previous term - would I still gain the marks?
Thanks again


Probably drop 2 on 8ii). You'll probably get 1 on 9iii).
Original post by nozzelf78
Thank you very much - are you doing the m2 ocr answers by any chance?


I looked in another M2 thread and saw a list of answers so I thought I probably wouldn't bother. If there is some debate I can do. I have a paper in my bag.
Original post by Mr M
I looked in another M2 thread and saw a list of answers so I thought I probably wouldn't bother. If there is some debate I can do. I have a paper in my bag.


Agreed, I am pretty sure most people on TSR know the answers to M2 by now if they took the exam.
Reply 17
By this, looks like I've lost around 10 marks :/.

Thanks Mr M though! If I may ask, what OCR papers will you be able to put up a mark scheme for this year? I've still got C3, C4, FP3, S1, S2, and D2 to come.
Thanks do much for this Mr M!
For 9ii) I got all mixed up. I put non unique for a=3 but then I proved the equations were consistent finding an exact answer, will this scrape me any marks? For part B I said unique solution but I stated DetD=0 as I mixed up my facts about determinants. You think that will get a mark?
I hope there was error carried forward for 10 because I got u^3+16u -9 but didnt get a value for u^2. so in part ii I used the correct method but found that (-b/a)^2 was 0 this meant my final answer was -35 as I got the aby = -3. I really hope I haven't sacrificed loads of marks here when i was just on the cusp of getting them. The grade boundaries better be low!
Original post by Sam596
By this, looks like I've lost around 10 marks :/.

Thanks Mr M though! If I may ask, what OCR papers will you be able to put up a mark scheme for this year? I've still got C3, C4, FP3, S1, S2, and D2 to come.


I'll do C3 and C4 and maybe some others.

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