The fuel tank of one type of hydrogen-powered car holds 70kg of magnesiumhydride. Calculate the volume of hydrogen gas, measured at room temperature and pressure,which would be produced if this amount of magnesium hydride reacted with water.
MgH2(s) + 2H2O(I) -----> Mg(OH)2(s) + 2H2(g)
The marking scheme says this :
Moles MgH2 = 70000 = 2659.6 (2660) (1)
26.32Moles H2 = 5319.2 (5320) (1) I've gotten to here, but I just cant figure out what to do to get the next answer.
Volume H2 = 1.28 × 105dm3(1)
Thanks for any help!
The answer is expressed in index form. Your value should be somewhere around 128,000 dm3 in standard form. (1.28 * 10^5)
After you have correctly gotten the moles of H2(g) which is 5319.2 using mole ratio from equation and mol of MgH2 (from your periodic table). Multiply that value by the molar volume at room temperature and pressure (RTP) which is always 24 dm3. You should get: 127,660.8 dm3 which is close enough. You can round up to get 128,000dm3. You can multiply that by 1000 to convert to cm3 if you want.
The Alkene is the nucleophile. The Alkene reacts with the Br-Br. How could BrOH even react? It would dissociate as BrO- and H+. And that equilibrium lies well to the left anyway.
The Alkene is the nucleophile. The Alkene reacts with the Br-Br. How could BrOH even react? It would dissociate as BrO- and H+. And that equilibrium lies well to the left anyway.
Well I don't have that much knowledge I'm afraid I just remember my teacher saying bromoalcohol forms with bromine water because HOBr inside bromine water whatnot
Well I don't have that much knowledge I'm afraid I just remember my teacher saying bromoalcohol forms with bromine water because HOBr inside bromine water whatnot
HoBr doesn't form. In AQ the bromine adds to one carbon of the double bond forming a carbocation as normal. The bromine is AQ so compared to the other nucleophile present (water) there is very little of the bromine - ions. Therefore the major product involves the water adding to the carbocation and then the extra hydrogen reacts with a lone pair from another water molecule forming an H3O (hydronium) ion
HoBr doesn't form. In AQ the bromine adds to one carbon of the double bond forming a carbocation as normal. The bromine is AQ so compared to the other nucleophile present (water) there is very little of the bromine - ions. Therefore the major product involves the water adding to the carbocation and then the extra hydrogen reacts with a lone pair from another water molecule forming an H3O (hydronium) ion
resitting unit two even though I got 83/100 (which was just an A), to get a higher A. Forgotten most of the content, so I'm starting my revision for this now
resitting unit two even though I got 83/100 (which was just an A), to get a higher A. Forgotten most of the content, so I'm starting my revision for this now
if the papers the same as last year uh oh . Or you could benefit from the low boundaries haha