Trigonometry

I did that, but I wasn't getting the right answers, I got my primary value as 0.886

Oh, well you don't need to find tan(x) as you originally thought in your original post! You just have to square root, and then use inverse tan. Notice though in part b) it is in terms of $2 \theta$, but part 1 was just in terms of $x$

Did you work out the angles for -root(3/2)?

I got that tan2theta is root 1.5, so I did the inverse of that which is where I got 0.886 from

I'm confused which bit your stuck on, is it the whole of q 7 or have you shown part a to be true and now your trying to do part b?

I'm confused which bit your stuck on, is it the whole of q 7 or have you shown part a to be true and now your trying to do part b?

Incorrect. Tan2theta is +root 1.5 AND -root 1.5. Square roots can be + and -

ALSO: is your calculator in degrees?

Yeah, I've done part a and I'm fine on part b up until after tan2theta = = or - root 1.5.
I'm fine up till then, after that I don't have a clue

Incorrect. Tan2theta is +root 1.5 AND -root 1.5. Square roots can be + and -

ALSO: is your calculator in degrees?

There's too many people all trying to help at once. I'll leave you guys to it.

crap no its in radians, sorry so the primary values are = and - 50.768 then?

but, as I'm sure your aware, there is more to be found. do you know how to do that?

yeh so for your first value of theta you would just half 50. whatever it was. but to find more values of 2theta within 0-360 you need to use whatever method you were taught such as looking at a tan graph or a quadrant method maybe? then half all those and ensure they are within 0 and 180

Adjust limits


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Sorry if you don't mind explaining how would I find out the values using a tan graph (I know how to draw one), my teacher has been ill for the last few months so we didn't properly go over it.