WJEC AS Physics PH1 May 19th 2015

Original post by Jonooo123

Did anyone else get a resistivity along the lines of 8x10^-8 for the wire? and a drift velocity of something like 5x10^-5?

I remember getting 10^-5 for drift velocity

Reply 142

With the graff with the train. I did a tangent and I got a weird acceleration. what was the acceleration? or in other words, what was the gradient?

Reply 143

PrimeLime

OP

12

Original post by rhungwilym

With the graff with the train. I did a tangent and I got a weird acceleration. what was the acceleration? or in other words, what was the gradient?

0.133333333333333333333333333333333333333333333333333333333333... ms^-2

Reply 144

Original post by PrimeLime

0.133333333333333333333333333333333333333333333333333333333333... ms^-2

I think I got something smaller than that but I don't remember. I just remember making the triangle massive on the paper

Reply 145

Original post by rhungwilym

I think I got something smaller than that but I don't remember. I just remember making the triangle massive on the paper

yeah mine was about 0.1375 I think, I'm sure there will be loads of tolerance in the mark scheme for that bit like ±0.05, doesn't sound like a lot but in the context it is!

Reply 146

Where did 48km/h come from? I put 50 because I am a tool. Also what was the velocity of it? I think I did 50,000/60x60? Something like that?

Reply 147

Original post by DirtyExamTables

Where did 48km/h come from? I put 50 because I am a tool. Also what was the velocity of it? I think I did 50,000/60x60? Something like that?

Can't remember the exact values, but you divide distance travelled (300m) by their respective speeds, this gives you the time taken. Do this for both AB and BA. Then to calculate mean velocity, you divide the total distance travelled (300+300=600) by the total time taken for AB and BA, which should give you 48km

Reply 148

Original post by thegayman

Can't remember the exact values, but you divide distance travelled (300m) by their respective speeds, this gives you the time taken. Do this for both AB and BA. Then to calculate mean velocity, you divide the total distance travelled (300+300=600) by the total time taken for AB and BA, which should give you 48km

48km/h sorry

Reply 149

Original post by DirtyExamTables

Where did 48km/h come from? I put 50 because I am a tool. Also what was the velocity of it? I think I did 50,000/60x60? Something like that?

It went at 40kmh for 7.5 hours and 60 for 5 hours. (40x7.5)+(60x5) = 600
600/12.5 = 48. For the next bit velocity = 0 because the resultant displacement is zero, it ends where it started!

Reply 150

Original post by thegayman

Can't remember the exact values, but you divide distance travelled (300m) by their respective speeds, this gives you the time taken. Do this for both AB and BA. Then to calculate mean velocity, you divide the total distance travelled (300+300=600) by the total time taken for AB and BA, which should give you 48km

ugh. I knew 50 was too good to be true :frown:

I didn't do very well. Will have to do better next year amongst all the a2 exams, otherwise I'll be working in McDonald's for the rest of my life

Reply 151

Original post by Jonooo123

It went at 40kmh for 7.5 hours and 60 for 5 hours. (40x7.5)+(60x5) = 600
600/12.5 = 48. For the next bit velocity = 0 because the resultant displacement is zero, it ends where it started!

oh great. I've done even worse than my already low expectations :redface:

Reply 152

Original post by DirtyExamTables

oh great. I've done even worse than my already low expectations :redface:

Have faith, the grade boundaries are likely to be low (I hope!!) as the paper was significantly harder than previous years

Reply 153

Original post by thegayman

Have faith, the grade boundaries are likely to be low (I hope!!) as the paper was significantly harder than previous years

It would be good to compile a list of all the quotes on answers people agree on. Because, so far, 4500 ohms is the only number I can recognise...

Reply 154

Original post by DirtyExamTables

It would be good to compile a list of all the quotes on answers people agree on. Because, so far, 4500 ohms is the only number I can recognise...

Hmm I would try but I can't remember question numbers only answers aha

Reply 155

Original post by Jonooo123

Hmm I would try but I can't remember question numbers only answers aha

and 4500 ohms is right :biggrin:

Reply 156

Original post by Jonooo123

and 4500 ohms is right :biggrin:

Yay, so far I'm on 5 marks out of 80. At one point I remember doing mgh - 0.5mv^2, that seem familiar? I know I got the next part wrong though, I forgot to use the horizontal distance given in the question

Reply 157

Original post by DirtyExamTables

Where did 48km/h come from? I put 50 because I am a tool. Also what was the velocity of it? I think I did 50,000/60x60? Something like that?

I did the same as you because I don't think it said the time in that particular question. it said later if I remember. in the graph.

Reply 158

Original post by rhungwilym

I did the same as you because I don't think it said the time in that particular question. it said later if I remember.

You have to work out the time, using time=distance travelled/speed

Reply 159