The Student Room Group

OCR (not MEI) C2 - Wednesday 20th May 2015

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Reply 60


y^2= 27
log3(y^2)= log3(27)
2log3(y) = log3(3) + log3(3) + log3(3) *move power of y in front of log
* 27= 3x3x3 so break apart using log rules
2log3(y) = 3 *loga(a) =1
log3(y)= 3/2
What happens when you are doing trigonometry and you get a negative angle ?
Reply 62
Original post by Kadak
What happens when you are doing trigonometry and you get a negative angle ?


Do you have a question as an example?
Reply 63
Original post by Kadak
Where did you get the 272 or the log after it ?

Sorry I forgot to press enter :P,
y²=27
log3 = log327
2log3y = 3
log3y = 1.5
https://68baf9f6baae001b7abe18b6e880c559742888e3.googledrive.com/host/0B1ZiqBksUHNYUlVQUzA0enkzVFU/Specimen%20QP%20-%20C2%20OCR.pdf
Question 5(ii) When I got my sin angles ,I got sin^-1(-2/5) which got me a negative angle.
Original post by Kadak
https://68baf9f6baae001b7abe18b6e880c559742888e3.googledrive.com/host/0B1ZiqBksUHNYUlVQUzA0enkzVFU/Specimen%20QP%20-%20C2%20OCR.pdf
Question 5(ii) When I got my sin angles ,I got sin^-1(-2/5) which got me a negative angle.


use cast diagram to find the positive angle then keep going like a normal question like this
Quick question ?Do we have to show the CAST diagram ?Can we draw two ,one for each angle Im finding ?
Reply 67
Original post by Kadak
https://68baf9f6baae001b7abe18b6e880c559742888e3.googledrive.com/host/0B1ZiqBksUHNYUlVQUzA0enkzVFU/Specimen%20QP%20-%20C2%20OCR.pdf
Question 5(ii) When I got my sin angles ,I got sin^-1(-2/5) which got me a negative angle.

That is no problem. Can you please give me a min to write it up :smile:
Can anyone help me with this log question please?

Find the roots of the equation 2log(base4)x - log(base4)(-7x+3)=-1/2?

I have got to 2x^2 + 7x - 3 = 0 but you have to use the quadratic formula to factorise this and I do not get the correct answer...have I made a mistake?

Thanks!
Reply 69
maths.png
Original post by Kadak
https://68baf9f6baae001b7abe18b6e880c559742888e3.googledrive.com/host/0B1ZiqBksUHNYUlVQUzA0enkzVFU/Specimen%20QP%20-%20C2%20OCR.pdf
Question 5(ii) When I got my sin angles ,I got sin^-1(-2/5) which got me a negative angle.
Original post by Issy :)
maths.png


I use the CAST method :frown:. Im confused ,I thought we woud add 180 to 19.5.For the engative angle,did you substract from 180 ?
Reply 71
Original post by Kadak
I use the CAST method :frown:. Im confused ,I thought we woud add 180 to 19.5.For the engative angle,did you substract from 180 ?


Do you have the answers? I have been doing maths all day so might have messed it up. My brain is literally fried. :wink:
(edited 8 years ago)
Reply 73
Original post by giantbecky
Can anyone help me with this log question please?

Find the roots of the equation 2log(base4)x - log(base4)(-7x+3)=-1/2?

I have got to 2x^2 + 7x - 3 = 0 but you have to use the quadratic formula to factorise this and I do not get the correct answer...have I made a mistake?

Thanks!


I got that equation as well, can you tell what paper this question is from.
Original post by Sahil_
I got that equation as well, can you tell what paper this question is from.


It's not from a paper, it's from this revision guide/textbook...I can tell you the answers if you want?
I thought maybe the answers were wrong but when I put them back into the original log equation they give -1/2 :frown:
Reply 75
No, I was right, I just got fed up writing out all the answers halfway through. I really can't explain the cast method as I have always been taught the graph way. Let me think a mo and see if I can explain it :smile:
Reply 76
Original post by giantbecky
It's not from a paper, it's from this revision guide/textbook...I can tell you the answers if you want?
I thought maybe the answers were wrong but when I put them back into the original log equation they give -1/2 :frown:


If you put the answers from the textbook into the equation does is also give -1/2?
Reply 77
Ok, so the 19.5 value is positive so can only be in the first and second quadrant yes (CAST so only A and S) therefore is 180-19.5.
The negative value, for sin to be negative it must be in the 3rd or 4th quadrant. Therefore, ignore the negative when typing into the calc then do 360-23.6 and 180+23.6
That is using the cast diagram (needed a min to jog my memory of the method)

Original post by Kadak
I use the CAST method :frown:. Im confused ,I thought we woud add 180 to 19.5.For the engative angle,did you substract from 180 ?
Original post by Sahil_
If you put the answers from the textbook into the equation does is also give -1/2?


the answers are 3 and 1/2 and actually I just tried 1/2 and I don't think that works as -7x1/2 +3 = -1/2 and you can't take logs of negative numbers...

So maybe the textbook is wrong? :s-smilie:
Original post by Issy :)
Ok, so the 19.5 value is positive so can only be in the first and second quadrant yes (CAST so only A and S) therefore is 180-19.5.
The negative value, for sin to be negative it must be in the 3rd or 4th quadrant. Therefore, ignore the negative when typing into the calc then do 360-23.6 and 180+23.6
That is using the cast diagram (needed a min to jog my memory of the method)


Thank you so much !

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