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WJEC AS Chemistry CH1 May 22nd 2015

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Is the examiner for ch2 the same as Ch1?
Reply 61
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Neyha
Try going through your notes with a whiteboard and just keep scribbling things down again and again, it works for me :smile:
Reply 62
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VeepFan
3
what specific examples/catalysts/reactions do we need to know... not processes and explanations, for CH1? any help would be vmapreeeeeciated
Reply 63
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goodies
9
Original post by VeepFan
what specific examples/catalysts/reactions do we need to know... not processes and explanations, for CH1? any help would be vmapreeeeeciated


I don't think there's any. That's the good thing about ch1.
Reply 64
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VeepFan
3
Original post by goodies
I don't think there's any. That's the good thing about ch1.


/amazing/
ImageUploadedByStudent Room1432242203.848143.jpg How is the answer A. Someone explain plz


Posted from TSR Mobile
Original post by dont leave blank
ImageUploadedByStudent Room1432242203.848143.jpg How is the answer A. Someone explain plz


Posted from TSR Mobile


well find the number of moles in 16 grams of SO2, which is 16/64.1 = 0.2496 moles ------- 64.1 is the Mr of SO2

you need to multiply 0.2596 by the Ar of Carbon (12) which gives: 0.2596 x 12 = 2.995 grams

and 2.995 grams rounded up to give 3 grams
(edited 8 years ago)
Reply 67
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goodies
9
Can somebody please explain to me how to get the answer to the question right at the bottom of the image in this link: http://gyazo.com/1120ddfcb97f58f8e624e930dba0e257.

It's the last question june 2010 incase you want to see it all.
Original post by goodies
Can somebody please explain to me how to get the answer to the question right at the bottom of the image in this link: http://gyazo.com/1120ddfcb97f58f8e624e930dba0e257.

It's the last question june 2010 incase you want to see it all.


I think its the mass of K times 2 OVER total mass times 100

Should be 56.6
Original post by Faisalshamallakh
well find the number of moles in 16 grams of SO2, which is 16/64.1 = 0.2496 moles ------- 64.1 is the Mr of SO2

you need to multiply 0.2596 by the Ar of Carbon (12) which gives: 0.2596 x 12 = 2.995 grams

and 2.995 grams rounded up to give 3 grams


Thanks 😅, i just couldn't think clearly...


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Holy crap what a brilliant paper. I'm well pleased with that
Original post by Jack1066
Holy crap what a brilliant paper. I'm well pleased with that


What did you get for the last question?
Some questions were alright, but the calculations and that catalyst question....what the hell was going on. Might as well ask for my resit form right now.
Original post by Questioner1234
What did you get for the last question?


What was it?
Original post by Jack1066
What was it?


The calculations
I think I got the temperature rise wrong (I had 2 degrees but I don't think its right), but I had the concentration the same for both the Hcl and NaOH.

So my energy released was wrong but I think I'll get error carried forward so I should get some marks
That was the most horrible paper ever?!
Original post by Qwertykeyboard15
That was the most horrible paper ever?!



I think it was a lot easier than the past papers I've done, I struggled on those but this I seemed okay...

Knowing my luck though, its more likely I thought it was easy because I was doing it all wrong
Reply 78
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Ser_
6
Original post by qwertykeyboard15
that was the most horrible paper ever?!


i'm so glad someone agrees
Reply 79
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Ser_
6
Anyone get -1.3Kj mol-1 for the last calculations question??

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