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WJEC AS Chemistry CH1 May 22nd 2015

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Reply 140
Original post by Sh4hid96
N2O5


Thankyouuuuuu. Correct :biggrin:
Reply 141
Original post by Ben_14
Thankyouuuuuu. Correct :biggrin:


Also, whats was the enthalpy change for the one but last page? i think mine was around -36.6KJmol?
Reply 142
Original post by Ser_
I had -417!


I had the same.
Original post by Ben_14
Also, whats was the enthalpy change for the one but last page? i think mine was around -36.6KJmol?


56.something
Reply 144
Original post by Ben_14
Also, whats was the enthalpy change for the one but last page? i think mine was around -36.6KJmol?


Mine was -1.3KJmol-1 but I've just realised I put the concentration as 'n' instead of the moles!!!! Sugarrrrrr
Original post by Sh4hid96
I got 18.9.


I got this aswell, but rounded to 19%
Original post by Ben_14
Also, whats was the enthalpy change for the one but last page? i think mine was around -36.6KJmol?

I got this aswell
What did everyone put for the volume? I had like 0.228 something? And what was the catalyst?
Original post by ZeroShun
I also put delta H as equal to Ef -Eb.


I should be Eb - Ef
Reply 149
Original post by Ser_
Mine was -1.3KJmol-1 but I've just realised I put the concentration as 'n' instead of the moles!!!! Sugarrrrrr

should've been something along the lines of

-50x4.12x6.2/0.025 (pretty sure that was the moles value)
then divide by a 1000 to convert joules to KJ
Original post by Formless
I should be Eb - Ef


No it shouldnt
Original post by Ben_14
should've been something along the lines of

-50x4.12x6.2/0.025 (pretty sure that was the moles value)
then divide by a 1000 to convert joules to KJ


Don't you only use the number of moles of one of the reactants
Reply 152
What did people put as the definition for molar mass?
Original post by Ser_
What did people put as the definition for molar mass?


Mass of one mole of a compound
Reply 154
Original post by Questioner1234
Don't you only use the number of moles of one of the reactants


well the entire equation had a 1:1:1:1 molar ratio so the moles would remain the same. I think it you had to work out the moles for NAOH which was 0.025. Make sense?
Original post by Questioner1234
No it shouldnt


Actually yeah my bad that is correct i forgot that deltaH is negative in exothermic, so Eb being larger. I guess i lost a mark then, however i know i did the graph right, just forgot about darn signs
Original post by Questioner1234
0.3something


Yes i got the same, Thought it was a bit too small, but i knew it had to be less than 2.4dm^3 as it was <0.1moles
Reply 157
Original post by Formless
Yes i got the same, Thought it was a bit too small, but i knew it had to be less than 2.4dm^3 as it was <0.1moles


What was the compound again? 2Ca(N03)2?
Original post by Ben_14
well the entire equation had a 1:1:1:1 molar ratio so the moles would remain the same. I think it you had to work out the moles for NAOH which was 0.025. Make sense?


Yeah I did the exact same method and got 56 with a temp change of 6.5 and volume of 25? What did you get as your answer.
Original post by Ben_14
What was the compound again? 2Ca(N03)2?


Yeah

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