The Student Room Group

AQA Further Maths FP1 June 5th 2015

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Reply 20
Original post by a123a
Lol. At one point I considered applying for Maths, but then I realised I don't like it as much as I thought. Chemistry is the best subject ever :biggrin: Beats maths any day.

On a more serious note, you don't really need super high UMS; anything >93% for Maths should be more than enough. They tend to give a lot of offers for Maths and let STEP reduce the numbers for them. But obviously aim for as high as you can! And I don't think having a low score in the odd module will matter too much.


I know, it's just that I want to leave myself some room for things like S1 and S2. I don't know why, but I find them a lot harder. :s-smilie:
Reply 21
Original post by Lau14
I think they both went well enough, definitely. If the official markscheme is right I only dropped about one mark on FP4, and other than the tricky bit at the end of FP3 it went smoothly and judging from the overall reactions the grade boundaries for that paper will be pretty low!


I've heard a lot about the last question of FP3 being really hard!
Reply 22
Original post by student0042
Maths isn't really sufficient but I guess D1 is a stepping to D2 which, at least to me, is more interesting.
Will you be sitting the FP2 exam or are you just self studying?


Just self studying since I'll need it for the admission test. I could do the exam, but I don't think there's any point.
Reply 23
Original post by PrimeLime
I've heard a lot about the last question of FP3 being really hard!


Yeah it was pretty awful, and it turns out both of the methods I tried were right, they just seemed too complicated so I stopped before finishing! Hopefully I left enough not crossed out to pick up a decent number of method marks, but it should be okay anyway.
Reply 24
Original post by PrimeLime
I know, it's just that I want to leave myself some room for things like S1 and S2. I don't know why, but I find them a lot harder. :s-smilie:


Yeah the written questions in stats trip me up and because the boundaries are relatively high, I'm losing potentially 5-10 UMS.
(edited 8 years ago)
Reply 25
Original post by a123a
Yeah the written questions in stats trip me up and because the boundaries are relatively high, I'm losing potentially 5-10 UMS.


Especially S2. They can easily make questions in S2 really hard if they want to. Some Poisson distribution questions in recent papers were quite tricky and I was actually unable to answer some of them even after thinking for a long time :s-smilie:.
Reply 26
Original post by Lau14
Yeah it was pretty awful, and it turns out both of the methods I tried were right, they just seemed too complicated so I stopped before finishing! Hopefully I left enough not crossed out to pick up a decent number of method marks, but it should be okay anyway.


Oh I hate when then happens in Maths - you try a correct method but it gets complicated so you end up assuming that it's wrong...
Reply 27
Original post by PrimeLime
Oh I hate when then happens in Maths - you try a correct method but it gets complicated so you end up assuming that it's wrong...


Yeah, fortunately that's unlikely in FP1!
Reply 28
I'm in!
Reply 29
Original post by C0balt
I'm in!


How are you finding FP1?
Reply 30
Original post by PrimeLime
How are you finding FP1?


It's okay. I understand them and find past papers easy EXCEPT that 2014 paper which I did for mock. It was horrendous lol thankfully the boundary was very very low so I could get 100UMS but not looking forward to our paper tbh
Reply 31
Original post by C0balt
It's okay. I understand them and find past papers easy EXCEPT that 2014 paper which I did for mock. It was horrendous lol thankfully the boundary was very very low so I could get 100UMS but not looking forward to our paper tbh


The paper this year is going to be trickier than ever...
What did you find hard about June 2014? Was it the sum of the trig solutions and/or the conic sections at the end?
For the trig summation I had to model the two general solutions as functions, do quite a lot of algebra and then sum two series to get the answer XD. It took me 10 minutes...
Reply 32
Original post by PrimeLime
The paper this year is going to be trickier than ever...
What did you find hard about June 2014? Was it the sum of the trig solutions and/or the conic sections at the end?
For the trig summation I had to model the two general solutions as functions, do quite a lot of algebra and then sum two series to get the answer XD. It took me 10 minutes...


They seem to have started making maths harder since last year
The entire paper was trickier than previous ones tbh. I usually only take less than 4 pages to do a paper but it took me 6 pages for the 2014 one lol
I quite liked the trig question where you had to realise it was an arithmetic series
Reply 33
Original post by C0balt
They seem to have started making maths harder since last year
The entire paper was trickier than previous ones tbh. I usually only take less than 4 pages to do a paper but it took me 6 pages for the 2014 one lol
I quite liked the trig question where you had to realise it was an arithmetic series


Yep they have. Even modules like C1. Most people think that this year's WJEC C1 exam was extremely difficult!
Yeah it was a fairly tough paper and I do like it when they actually test your insight and problem-solving skills, even if only to a small extent.
(edited 8 years ago)
Reply 34
Original post by PrimeLime
Yep they have. Even modules like C1. Most people think that this year's WJEC C1 exam was extremely difficult!
Yeah it was a fairly tough paper and I do like it when they actually test your insight and problem-solving skills, even if only to a small extent.


I liked the 2014 paper, but I would be mentally damaged if I see it in my exam although I'd probably do fine
How did you find C1 and C2? Did you take them this year
Reply 35
Original post by C0balt
I liked the 2014 paper, but I would be mentally damaged if I see it in my exam although I'd probably do fine
How did you find C1 and C2? Did you take them this year


Yeah I did the WJEC C1 and C2 exams. C1 was harder than it has ever been before, but that was to be expected. C2 was a fairly standard paper, maybe slightly harder. But the last question on both papers threw almost everyone for some reason. In C1 it was an optimisation problem for the length of a fence L on a farm (so you have to find dL/dx and d2L/dx2 etc.) and for C2 it was finding the ratio between the major and minor segments of a circle (where one segment had one colour of flowers and the other had another colour of flowers). So WJEC seemed to like land problems this year...
Reply 36
Original post by PrimeLime
Yeah I did the WJEC C1 and C2 exams. C1 was harder than it has ever been before, but that was to be expected. C2 was a fairly standard paper, maybe slightly harder. But the last question on both papers threw almost everyone for some reason. In C1 it was an optimisation problem for the length of a fence L on a farm (so you have to find dL/dx and d2L/dx2 etc.) and for C2 it was finding the ratio between the major and minor segments of a circle (where one segment had one colour of flowers and the other had another colour of flowers). So WJEC seemed to like land problems this year...

Oh so you do different board for FM?
With AQA they were harder than pre 2014. C1 was slightly harder than 2014 but C2 was easier than 2014. C1 had a cylinder question where people forgot how to calculate the surface area haha I did well in both but kicking myself for a silly mistake in C2 - hoping the UMS boundaries would be low to land me above 95UMS really
Fp1 should be fine until they decide to add in excessive transformation - I don't like those tbh
Reply 37
Can someone explain how to do this question please?

Verify that (root5 - i) is a root of the equation:

(2+i root5)z = 3z*

I know the answer will be simple, but not revised complex numbers in a while and my minds gone totally blank haha :s-smilie:
Reply 38
Original post by Adam_98
Can someone explain how to do this question please?

Verify that (root5 - i) is a root of the equation:

(2+i root5)z = 3z*

I know the answer will be simple, but not revised complex numbers in a while and my minds gone totally blank haha :s-smilie:


Plug that into z and change the sign to + (the conjugate) then plug into z*
Reply 39
Original post by C0balt
Plug that into z and change the sign to + (the conjugate) then plug into z*


Thanks!

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