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Edexcel FP2 June 2015 - Official Thread

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OK so I think I ****ed up slightly. I forgot to square root for the modulus in i think Q2 and then I forgot to square the modulus in the transformation question. I think everything else is fine. Can I still get 90+ ums?
Reply 281
Original post by kingaaran
That's good then - at least I'm not the only one.


It's the way you're taught in C4. Using Sin and Cos addition furmulae to evaluate integrals with trigs multiplied together
Original post by kingaaran
Yep, I have it on me. I can scan it when I get home, but at the moment I can only post the questions?


Scanned version would be ideal. Thanks a lot really.
Original post by TeeEm
I am not planning to do solutions now.
I have a list of currently 95 papers to do solutions for and this will slot somewhere mid-July in my do lists.

However it will be nice to see the paper.


Original post by kingaaran
Yep, I have it on me. I can scan it when I get home, but at the moment I can only post the questions?


Original post by aidinpoori
Honestly? Have you scanned it? I'd love to see it please. I teach FP2 and am very concerened for my students. I know exactly what they can do and what they can't do. Jst wanted to check it please. Much appreciated.


See the other thread
http://www.thestudentroom.co.uk/showthread.php?t=3156193&page=63
post 1246
Yeah i did that!
Q1)

(a) Use algebra to find the set of values of x for which x+2>12x+3 x+2 > \frac{12}{x+3}

(b) Hence, or otherwise, find the set of values for x for which x+2>12x+3 x+2 > \frac{12}{|x+3|}

Q2)

z = -2 + 2(root3)i

(a) Find the modulus and argument of z

Using de Moivre's theorem,

(b) find z6z^6, simplifying your answer

(c) find the values of w such that w4=z3w^4 = z^3, giving your answers in the form a+ib, where a, b are real numbers.

3)

Find, in the form y=f(x), the general solution of the differential equation

tanxdydx+y=3cos2xtanxtanx\frac{dy}{dx} + y = 3cos2x tan x

4)

(a) Show that

r2(r+1)2(r1)2r2=4r3r^2(r+1)^2 - (r-1)^2r^2 = 4r^3

(b)

use the identity given in (a) and the method of differences to show that

(13+22+33...+n3)=(1+2+3...+n)2(1^3+2^2+3^3...+n^3) = (1+2+3...+n)^2

Q5)

A transformation T from the z-plane to the w-plane is given by

w=zz+3i w=\frac{z}{z+3i}

The circle with equation |z| = 2 is mapped by T onto the curve C.

(a) Show that C is a circle and find the centre and radius of C

The region |z| <= 2 in the z-plane is mapped by T onto the region R in the w-plane.

(b) SHade the region R on an argand diagram

Q6)

The curve C, shown in Figure 1, has polar equation r=3a(1+cosθ) r = 3a(1+cos\theta)

The tangent to C at the point A is parallel to the initial line.

(a) Find the polar coordinates of A.

The finite region R shown shaded in Figure 1 is bounded by the curve C, the initial line and the line OA.

(b) Use calculus to find the area of R.

Q7)

y=tan2xy=tan^2x

(a) Show that d2ydx2=6sec4x4sec2x\frac{d^2y}{dx^2} = 6sec^4x - 4sec^2x

(b) Hence show that d3ydx3=8sec2xtanx(Asec2x+B)\frac{d^3y}{dx^3} = 8sec^2x tan x (Asec^2x +B), where A and B are constants to be found.

(c) Find the taylor series expansion of y=tan2xy=tan^2x, in ascending powers of x - (pi/3), up to and including the term in [x - (pi/3)]^3

Q8)

(a) Show that the transformation x=eu x=e^u transforms the differential equation


x2d2ydx27xdydx+16y=2lnx x^2\frac{d^2y}{dx^2} -7x\frac{dy}{dx} + 16y = 2lnx (i)

into the differential equation

d2ydu28dydu+16y=2u \frac{d^2y}{du^2} -8\frac{dy}{du} + 16y = 2u (ii)

(b) Find the general solution of the differential equation (ii), expressing y as a function of u.

(c) Hence obtain the general solution of the differential equation (i).
Reply 286
Original post by Anshul6974
That's what I got!


mine is pretty much the same as yours!! but for q3 i had sth like cosecxln()... maybe its just coz i didn't simplify it ??
Reply 288
why is this thread so quiet ...?
Anyone know if Arsey has posted for this yet??
does anyone know the marks for each question?
(edited 8 years ago)
Original post by TeeEm
why is this thread so quiet ...?


Most people are on the other one.
All I know is that Edexcel is BAE after that exam! ☺️ Oxford here I come!


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Reply 293
Original post by kingaaran
Integral of 3cos2xsinx

Is it okay to integrate 3/2(sin3x -sinx) instead?


I also integrated it this way! ended up with something like y = -cos3x/2sinx + 3cotx/2... etc or something like that, hard to remember! hopefully won't need to simplify that anymore!
Original post by StarvingAutist
I got inside.
Is anything there wrong?

I got it inside too.I thought of z=0 (which satisfies IzI=<2) then w=0 which is inside the circle .
Did you mentioned that the circle itself satisfies this. I forgot...
Original post by V0ldemort17
All I know is that Edexcel is BAE after that exam! ☺️ Oxford here I come!


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Oxford Brookes?
(edited 8 years ago)
Original post by Idomaths
u chat so much sh it


Don't know if I do bro.
Don't be jealous bro.


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Original post by MrBowcat
Oxford Brookes?


University of Oxford, you might not have heard of it but it's a pretty big deal


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Original post by V0ldemort17
University of Oxford, you might not have heard of it but it's a pretty big deal


Posted from TSR Mobile


Oh cool. You heard of Harvard?
Original post by kingaaran
cos2xsinx = sin3x - sin x

And then I integrated that. Is that fine?


Yeah this will be fine I wrote sin3/2x-sinx/2 because im stoopid and now ill only get about 85 ums

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