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Edexcel A2 C3 Mathematics 12th June 2015

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Xtreme?

never heard of them..
where did you get them?

https://www.dropbox.com/sh/oz0s4m3nf7rocug/AAD1Uy9ta4C7iEJX8H_e4jZ8a/Core/C3?dl=0

Just in the link from PhysicsMathstutor... perhaps they go by a different name?

Reply 981

aersh8

Original post by Artfanatic

https://www.dropbox.com/sh/oz0s4m3nf7rocug/AAD1Uy9ta4C7iEJX8H_e4jZ8a/Core/C3?dl=0

Just in the link from PhysicsMathstutor... perhaps they go by a different name?

LOL!

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Reply 982

Medicjug

Hahaha they are the IYGB ones

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Reply 983

MissC123

Guys iv never really understood CAST diagrams. I've always only used the formulae. Should I try learn them now?

Reply 984

Medicjug

Original post by MissC123

Guys iv never really understood CAST diagrams. I've always only used the formulae. Should I try learn them now?

I would recommend carrying on with what your using now. What might be beneficial is familiarising yourself with the graphs

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Reply 985

Anon-

Original post by MissC123

Guys iv never really understood CAST diagrams. I've always only used the formulae. Should I try learn them now?

Well if you've been fine without out them, then there's no reason to learn them. However if you are having trouble then make sure to learn it, there's nothing complicated about them and you should be able to get the hang of them instantly. Check out the videos about them on examsolutions.

Reply 986

TeeEm

Original post by Artfanatic

https://www.dropbox.com/sh/oz0s4m3nf7rocug/AAD1Uy9ta4C7iEJX8H_e4jZ8a/Core/C3?dl=0

Just in the link from PhysicsMathstutor... perhaps they go by a different name?

yes, they are my papers ...
they are called IYGB
extreme, my

Reply 987

danlocke

Just about finished the solomon papers and have a couple of questions before Friday:

What are the chances of one of these: "Prove, by counter-example, that the statement “ln(3x² + 5x + 3) ≥ 0 for all real values of x” is false." sort of proof questions coming up?

Also when you demonstrate change of sign to prove a root lies in a particular interval is it important to mention that the function is continuous as they do in the solomon mark schemes? Thanks!

Reply 988

Bustamove

when talking about the root, how exactly do you word it? do you just write "there's a sign change, therefore root = (insert root here)"
I'm always unsure on what to write.... can anyone clarify for me? thanks

Reply 989

gcsestuff

Teem are you sitting this exam

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Reply 990

Anon-

Original post by danlocke

Original post by Bustamove

when talking about the root, how exactly do you word it? do you just write "there's a sign change, therefore root = (insert root here)"I'm always unsure on what to write.... can anyone clarify for me? thanks

Mark scheme from an Edexcel paper: http://i.imgur.com/Fxnjm75.png

As you can see they put the continuous function in brackets, all you have to put as conclusion is: change of sign, therefore root at X for the final mark

(edited 8 years ago)

Reply 991

Bustamove

Original post by Anon-

ah i see... would I need to say that root is in between ae(2.3585,2.3595) or do i just go straight and say a=2.359?

(referring to the link you sent me, sorry I can't do the symbols above, so i just used letters which look similiar)

Reply 992

danlocke

Original post by Anon-

Perfect, thanks.

Reply 993

it's a me, mario

Does anyone know how to derive factor formulae? On page 125 it says:

sin(A+B) + sin(A-B) = 2sinAcosB
Let A+B = P and A-B = Q

Then A=(P+Q)/2 and B = (P-Q)/2
This is the part i dont get.. How does A and B equal that?

Shouldnt A = P-B and B = A-Q?
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Reply 994

Lochy99

Original post by it's a me, mario

You get simultaneous equations here so when you add them, you get:

P+Q= (A+B)+(A-B)
P+Q= 2A
A= (P+Q)/2

When you minus them you get:

P-Q= (A+B)-(A-B)
P-Q= 2B
B= (P-Q)/2

Reply 995

Anon-

Original post by it's a me, mario

You shouldn't have to worry about it. It says nothing about factor formulae in our specification.

Reply 996

it's a me, mario

Original post by Lochy99

You get simultaneous equations here so when you add them, you get:

P+Q= (A+B)+(A-B)
P+Q= 2A
A= (P+Q)/2

When you minus them you get:

P-Q= (A+B)-(A-B)
P-Q= 2B
B= (P-Q)/2

Aaah, i get it now. Thanks :yy:

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Reply 997

it's a me, mario

Original post by Anon-

You shouldn't have to worry about it. It says nothing about factor formulae in our specification.

Are you sure? No wonder it's never come up on a past paper :dontknow:

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Reply 998

XxKingSniprxX

Original post by it's a me, mario

Are you sure? No wonder it's never come up on a past paper :dontknow:

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I asked that question before couple days ago when I finished recapping C3 theory.

I did x12 past papers for my C3 mock back in December and never came across it. I'm assuming it's not on our specification. The same with modulus with inequalities.