AQA Physics PHYA4 - Thursday 11th June 2015 [Exam Discussion Thread]

What paper is it

thanks for your help I see it now! Think I'm getting a little tired



I'm glad you feel so comfortable doing this exam that you feel like you need to talk down at others. What's 'obvious' to you might not be obvious to other people so sit down please. This is a study help thread not a study brag thread.

for SHM (the left one), acceleration always acts towards equilibrium and for circular motion, acceleration acts towards the centre (centripetal acceleration). At the initial time therefore, acceleration for the mass-spring system is downwards and the particle in circular motion is upwards because there's where the centre is. After half an oscillation, the particle in circular motion will be at the top and the mass on the spring will be at the bottom so opposite accelerations. Hope this helps

Can anyone please help me with question's 19, 20 & 21 on the June 14 paper. Thanks

Hi.

Basically we need to find momentum which is mass x velocity.

We can find mass as we have density and volume.

Then we have the Area. We can use to find the length of the pipe to as A X L = V

The length gives use the speed of the water coming out.

Hence, v * m gives us the answer.

Volume is actually just 2x10^-4. You get a hint from the units, its m^3 PER SECOND. and the answer they want is per second

Hey guys does anyone know how to calculate the time period for this:
January 2011



The correct answer is B but my calculations can never get that answer.
Apparently we are supposed to use ω²r = 9.81

Thanks

Hey guys does anyone know how to calculate the time period for this:
January 2011



The correct answer is B but my calculations can never get that answer.
Apparently we are supposed to use ω²r = 9.81

Thanks

Anybody know of any good videos for magnetic fields?

anybody know of any good videos for magnetic fields?

Hey guys does anyone know how to calculate the time period for this:
January 2011



The correct answer is B but my calculations can never get that answer.
Apparently we are supposed to use ω²r = 9.81

Thanks

might help https://www.youtube.com/watch?v=MJGRVso9xTo&list=PL_1rV5tkHU7QzmFX3VRReiGJBuKXhudf6&index=6

Hey guys does anyone know how to calculate the time period for this:
January 2011



The correct answer is B but my calculations can never get that answer.
Apparently we are supposed to use ω²r = 9.81

Thanks

Can someone pls help me on this have no clue

What are the unit for impulse and change in momentum


Posted from TSR Mobile

mg=mw²r
g=w²r
T²/4π²=r/g
T=√(4π²r/g)