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AQA Physics PHYA4 - Thursday 11th June 2015 [Exam Discussion Thread]

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Original post by QueNNch
Hey guys does anyone know how to calculate the time period for this:
January 2011



The correct answer is B but my calculations can never get that answer.
Apparently we are supposed to use ω2r = 9.81

Thanks :smile:


mw^2r = GMm/r^2

rearranges to

w = (GM/r^3)^1/2

You get the answer in seconds, so divide it by 3600 and it should be 1.4 hours.

Make sure you cube the radius
Original post by Dante991
yeah me too, 19 was just like what


Tbh I'm like that with most of these mc questions and it's not good when we're just over 12 hours away from the exam! :frown:
Could you help me with 20 and 21 please if you got them? Thanks.
Anyone mind explaining Q15 of multiple choice 2014?
Original post by saad97
Tbh I'm like that with most of these mc questions and it's not good when we're just over 12 hours away from the exam! :frown:
Could you help me with 20 and 21 please if you got them? Thanks.


Tell me about it :redface:

Which paper are those questions from?
Original post by frankiejayx
Anyone mind explaining Q15 of multiple choice 2014?


Post a link to the question pls
Original post by saad97
Tbh I'm like that with most of these mc questions and it's not good when we're just over 12 hours away from the exam! :frown:
Could you help me with 20 and 21 please if you got them? Thanks.


I'm looking for someone to show me how to do them too, absoulte killer paper
Original post by Dante991
I'm looking for someone to show me how to do them too, absoulte killer paper


I'll try help link me the questions
Original post by Dante991
I'm looking for someone to show me how to do them too, absoulte killer paper


I hope ours is much more straight forward but I doubt it considering how my exam's have gone so far this year, I've just lost all motivation to revise -_-
I'm going to fail ...
Reply 3710
1433964923046-1519872357.jpg
Original post by C-king
BUMP
Original post by DanielWall96
I'll try help link me the questions


http://filestore.aqa.org.uk/subjects/AQA-PHYA41-QP-JUN14.PDF

19, 20 & 21 please, thanks.
Original post by samlyon


Anyone? I'm just confusing myself


so each charge is providing half the potential
25/2 = 12.5

The potential from P is doubled as the distance is halved so = 25
The potential from Q is decreased by 1/1.5 so becomes 8.333333333
25 + 8.3333333= 33.3

C
Reply 3714
Original post by QueNNch
Hey guys does anyone know how to calculate the time period for this:
January 2011



The correct answer is B but my calculations can never get that answer.
Apparently we are supposed to use ω2r = 9.81

Thanks :smile:


If the object is to appear weightless, then the centripetal force needs to be equal to the weight, so that the resultant force is zero. Therefore mg = mw2r. The masses cancel each other out, so that gives you w2r = 9.81. Then substitute 2pi/T for w and rearrange to get the answer. :smile:
Thanks a lot @JaySP @C-king @DanielWall96 @Klaxoii @AR_95 @jh52
You all were really helpful. Thanks a lot!
It all makes sense now :biggrin:

Rep'd
Original post by JaySP
1433964923046-1519872357.jpg


ahh thanks, I was doing this but thought it was too much working for one mark, these questions are too deceptive
Original post by C-king
ahh thanks, I was doing this but thought it was too much working for one mark, these questions are too deceptive


Don't ever think that with MC. It can vary from plugging into an equation without doing any work, to 3 or 4 step questions
Hi
Does anyone have any ideas about what the 6 marker could be on?
Original post by C-king
ahh thanks, I was doing this but thought it was too much working for one mark, these questions are too deceptive


Thanks for this, I started off correctly but didnt know you divided the 2 equations

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