Edexcel Unit 4: Physics on the Move 6PH04 (11th June 2015)

Guys, during the anhiliation of electron and positron, do we always multiply by 2 in the calculations?

Guys, during the anhiliation of electron and positron, do we always multiply by 2 in the calculations?

because twice the same mass

DO you get how to do this question?

Two protons, eparated by a distance x, experience a repulsive force F. If the serparation is reduced to x/3, the force between the protons will be:

THe answer is 9F, but I keep getting 3F?

DO you get how to do this question?

Two protons, eparated by a distance x, experience a repulsive force F. If the serparation is reduced to x/3, the force between the protons will be:

THe answer is 9F, but I keep getting 3F?

could someone please briefly explain magnetic flux?and flux linkage? and what flux cutting is?

also when do you use the thumb rule or the left hand rule

could someone please briefly explain magnetic flux?and flux linkage? and what flux cutting is?

also when do you use the thumb rule or the left hand rule

Magnetic Flux Density (Magnetic Field Strength, B) is a measure of the number of magnetic flux 'lines' per unit area.

So if you multiply B by the area you're dealing with:

Magnetic Flux per unit area x Area = Magnetic Flux (ф)
This is then the amount of magnetic flux cutting the area you're dealing with, whether that be a coil or something.

This multiplied by the number of turns in the coil is the Flux Linkage (Փ):

Փ = Nф
= NAB

Then using Faraday's law you can calculate the magnitude of emf induced.

Hope it helped

(Someone correct me if I'm wrong please)

These 3 pages explain everything

https://270dd1fec3d16900cdb57f52003e6e39212d75a7.googledrive.com/host/0B1ZiqBksUHNYOGF3X0VfdU5uT1k/Detailed-Notes-with-Examples/Electric-and-Magnetic-Fields/Magnetic%20Fields.pdf

Why dont high speed roads have sharp bends?


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F=kQ1Q2/r^2
The distance b/w the two proton is r. And it is an inverse square relationship because F is propotional to 1/r^2 so F also gets squared.
Sorry idk how to explain it. Do you understand tho?

R^2. That is why F=kQQ/(r^2) It is 9F

As F=mv^2/r, the velocity will be high and the sharp bend will have a small radius. So, the required centripetal force to maintain circular motion, will be greater than the maximum frictional force between the tyres and road of the car. So the car will slide off the road.

ALo do you guys get why the time ha to be 0.125s for the calculation in 18b?
http://qualifications.pearson.com/content/dam/pdf/A%20Level/Physics/2013/Exam%20materials/6PH04_01R_que_20130613.pdf

why is it that the total momentum has to be zero when we are colliding particles?

Apparently this is the casein jan 14 IAL but then another paper it is not necessary? Edexcel can **** off with there bull****.


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yh i just did that paper and i am confused af. After today's chemistry flop i have to make up for it in physics and this paper makes like 0 sense to me

When to use KE = p²/2m vs KE = ½mv²?

And any chance of needing protractors or compasses?