This discussion is now closed.

Check out other Related discussions

OCR Physics A G484 - The Newtonian World - 11th June 2015

Although the first couple of questions were a bit iffy, the paper overall wasn't too bad; almost, dare I say it, easy. I would say the boundaries will be as follows;

100% UMS: 52
90% UMS: 45
A: 40
B: 36
C: 32
D: 29
E: 24

That seems fair, but shouldn't 100%ums be 50 according to those A and A* grade boundaries?

Reply 1481

Elcor

14

Original post by a123a

Last year was 39 for A 43 for A* and I'm guessing 47 for 90ums? So if you say this paper was harder than last years I expect the grade boundaries to be similar. So hopefully we both have full ums.

I think the boundaries will be higher than last year but still below average.

Posted from TSR Mobile

Reply 1482

a123a

14

Original post by olil1996

Yeah, I think that would probably get a mark, what did you get as your final answer?

That's good. I can't remember exactly but I know it wasn't 1.5x10^7.

Reply 1483

rachelc142

11

Original post by randlemcmurphy

Anyone think the exam got easier as it went on?

definitely ! Q1 & 2 were odd. rest was ok.
felt like the resonance question was disguised well.

Posted from TSR Mobile

Reply 1484

HMusa

1

What the actual **** was that? I checked the front page of my paper 3 times during the exam to make sure I was doing the right paper fml

Reply 1485

steffanwb

1

That first question really threw me off, no idea how I did because of that. Gotta make up for it in G485 now!

Reply 1486

chem@uni

9

Original post by rachelc142

definitely ! Q1 & 2 were odd. rest was ok.
felt like the resonance question was disguised well.

Posted from TSR Mobile

I agree

Posted from TSR Mobile

Reply 1487

a123a

14

Original post by Elcor

I think the boundaries will be higher than last year but still below average.

Posted from TSR Mobile

Yeah I agree with that.

Reply 1488

SH0405

15

Original post by a123a

That seems fair, but shouldn't 100%ums be 50 according to those A and A* grade boundaries?

Technically, yes. I'm sorry.

Reply 1489

kateyl

3

Original post by Elcor

For the second the period is constant but the amplitude decreases over time

Posted from TSR Mobile

Crap, I didn't put the amplitude decreasing over time but I just drew a second sinusoidal graph with a lower amplitude/max velocity (forgot what was on the y axis), would that get me one mark?

Reply 1490

JoeMartin

Does anyone actually have an answer for the first question? I was sitting there like I swearrr that students right and I can definately not think of TWO reasons otherwise. Made some stuff up about forces acting from the same point in the end

Reply 1491

Elcor

14

Original post by kateyl

Crap, I didn't put the amplitude decreasing over time but I just drew a second sinusoidal graph with a lower amplitude/max velocity (forgot what was on the y axis), would that get me one mark?

Probably 1/3

Posted from TSR Mobile

Reply 1492

Bjc00

2

anyone say energy lost was due to light because it was a laser, so took more time

Reply 1493

alanconnel

4

for the inital acceleration i can remeber what i got but i did mass times by velocity then divided by 1/rate or what ever it said. then used f=ma to calculate acceleration

Reply 1494

Tazmain

8

Original post by kateyl

Crap, I didn't put the amplitude decreasing over time but I just drew a second sinusoidal graph with a lower amplitude/max velocity (forgot what was on the y axis), would that get me one mark?

That's what I did, thought because it was a constant force, amplitude would be lower, but not decreasing...

Reply 1495

BrokenS0ulz

3

Original post by JoeMartin

Does anyone actually have an answer for the first question? I was sitting there like I swearrr that students right and I can definately not think of TWO reasons otherwise. Made some stuff up about forces acting from the same point in the end

idk I put that N and W are not the same type of force. They needed to be the same type to obey newton's third law.

Reply 1496

L'Evil Fish

OP

18

I said photo electric effect...

G482 knowledge right there

Reply 1497

Sam596

2

Original post by JoeMartin

Does anyone actually have an answer for the first question? I was sitting there like I swearrr that students right and I can definately not think of TWO reasons otherwise. Made some stuff up about forces acting from the same point in the end

The equal and opposite reaction force must be the same type of force (i.e. not one a normal reaction and one a weight) and also must be acting on a different body

Reply 1498

The Room Student

2

Original post by Tazmain

That's what I did, thought because it was a constant force, amplitude would be lower, but not decreasing...

If there's a constant resistive force then there's a constant deceleration.

If there's a constant deceleration then, well I'm pretty sure, the amplitude decays exponentially with time.