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AQA Physics PHYA4 - Thursday 11th June 2015 [Exam Discussion Thread]

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Original post by Disney0702
How is the first question acceleration.
Is rate of change of momentum really acceleration?


No. It's force.


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Original post by QueNNch
Well the motion is horizontal so weight is NOT included.

Vertical components and horizontal components are independent (we learned this is AS Unit 2)


Damn!
Original post by Will177
I think I just did mv^2/r = T because its horizontal and weight is verticle. Can't remember what value I got

I think thats wrong because the weight of particle is not taken into account. I did T - mg = mv^2/r
I put Weber Turns as the units...correct or?
Original post by Disney0702
How is the first question acceleration.
Is rate of change of momentum really acceleration?

Did you put weight?
Original post by Disney0702
Grade boundary predictions?


55 for A*
50 for A
etc...
Rate of change of momentum is Ns/s = N?
Original post by Disney0702
How is the first question acceleration.
Is rate of change of momentum really acceleration?


Yeah, thats how F=ma is derived


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Original post by Humbers
It was rotated horizontally so weight is perpendicular to centripetal force therefore ignored

T = mv^2/r 0.25 x 8.6^2 / 1.5 = 12.3N


I put T = +F
Original post by DannySmith420
I think thats wrong because the weight of particle is not taken into account. I did T - mg = mv^2/r


It said assume string is horizontal though


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Original post by Mehrdad jafari
Here are my answers. The ones I'm not sure with i have mentioned next to them.

I have failed to take the answer of one of the MC questions. Let me know if you found which one.
I would be very happy if you could correct the ones that are not right :smile:
ImageUploadedByStudent Room1434019809.052314.jpg


Thanks for putting them!

I think you question 17 is incorrect because the question asked for the number on electrons on the NEGATIVE plate ONLY. Therefore the answer is half of what you got. (something like 2.2 x 10^10)

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(edited 8 years ago)
Original post by fruity97
I got 15N at first for tension! But I remember changing it towards the end to 12N because I didn't include the weight I think? Stil not sure which is right but they said horizontal so I changed it


Yeah that's why I think it's wrong :/
Original post by Mehrdad jafari
Here are my answers. The ones I'm not sure with i have mentioned next to them.

I have failed to take the answer of one of the MC questions. Let me know if you found which one.
I would be very happy if you could correct the ones that are not right :smile:
ImageUploadedByStudent Room1434019809.052314.jpg


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Pretty sure 22 was 1/rt2 maybe you forgot to root each side?
Original post by Mehrdad jafari
Here are my answers. The ones I'm not sure with i have mentioned next to them.

I have failed to take the answer of one of the MC questions. Let me know if you found which one.
I would be very happy if you could correct the ones that are not right :smile:
ImageUploadedByStudent Room1434019809.052314.jpg


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First one is weight
Omg. I did not have enough time!! :'(
Guessed like some of the MC question. Fml.

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Original post by Fred Cantoni
No. It's force.


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Yh thats what I thought as well. Did u put weight as your answer?
Original post by NEWT0N
This is an unfair advantage for you then, because if they decide to mark it as "150 ohms" then people who got confused by the "150 k ohms" will maybe have drawn a different current intercept due to the confusion. So they would have to mark it like this I think:

Any current less than the original current should get the first mark

Shallower gradient gets the second mark

Anyone agree?


Sounds fair!
What about the 3rd mark?


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Original post by QueNNch
Thanks for putting them!

I think you question 17 is incorrect because the question asked for the number on electrons on the NEGATIVE plate ONLY. Therefore the answer is half of what you got. (something like 2.2 x 10^30)

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Damn, yeah, if they asked for one of the plates only then its half


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Original post by fruity97
Yeah what we're aqa playing at! Did they mean 150kohms? My graph was so small

Surely if they were charged with the same voltage the initial current should be the same. They were juat discharged through different resistors. So I drew a shallower graph?😕
Original post by Mehrdad jafari
Yeah, thats how F=ma is derived


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So shouldn't it be a force unit not acceleration?

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