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Edexcel A2 C3 Mathematics 12th June 2015

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Reply 1580
Avatar for Hudl
Hudl
16
Original post by Hudl
Can I ask for part b of this question why it isn't:

-(x-a) = 3x + 5a

For where the positive part of the graph meets the negative part help please Solomon paper L Q6)

ImageUploadedByStudent Room1434026108.479254.jpg


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Can someone please help me with this
Original post by Maham88


The C3 and C4 paper are combined into one large paper?
Original post by JamieF95
Just had a look at gold papers. Aren't they just a mixture of questions from the actual Edexcel papers?


yeah i know that. But they have levels like G1,2,3 and 4. (increasing difficulty) and its probably the best source of practice because they are mixed up questions from old and new papers
Original post by TheRaspberry
Hi all is the differential of e^x cubed as follows: 3^x squared + e^x cubed

Do you do this by the chain rule, a bit confused :P B


yes that is correct
Original post by it's a me, mario
Yeh, try doing that in the exam bro

Let me know how it goes :yes:

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nice joke bro
why does e^x have an asymtote as 0.

If x= -100000 for example, y = 0
Original post by Hudl
Can someone please help me with this


It would have something to do with the graph i think.


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Original post by TheRaspberry
Hi all is the differential of e^x cubed as follows: 3^x squared + e^x cubed

Do you do this by the chain rule, a bit confused :P B


It is 3^x squared times e^x cubed not plus.
Original post by TheRaspberry
Hi all is the differential of e^x cubed as follows: 3^x squared + e^x cubed

Do you do this by the chain rule, a bit confused :P B


It looks like you've used the product rule there. If it's (e^x)^3, then by the chain rule that would be 3(e^x)^2 * e^x, or 3(e^x)^3. That's differentiating the function of the function and multiplying by the differential of the thing inside the brackets.

Original post by suyoof123
why does e^x have an asymtote as 0.

If x= -100000 for example, y = 0


It's tiny, but not 0. if e^-x = 0, then ln(-x) = ln(0) = math error, so I guess e^-x can't be 0.
(edited 8 years ago)
Original post by Hudl
Can someone please help me with this


it is -x - a, yours expands to -x + a which is inconsistent with the equation you are given
Reply 1590
Avatar for 11234
11234
8
Original post by Hudl
Can someone please help me with this


I'll give you a hint, there are three situations we need to consider, when x<-5a/3 -5a/3<x<0 and x>0
feel like I know everything I can for this exam but still sooo nervous
What is the hardest and most beneficial c3 paper to do?
Original post by Elm Tree
The C3 and C4 paper are combined into one large paper?


yeah i think they do c3 and c4 together
does anyone have some good notes or sources for drawing ln and e power x graphs and their translations respectively? including finding the domain and range

would be really grateful thank you :smile:
Can someone explain what happens to the graph is transformed by the function f(|x|)
Reply 1596
Avatar for Hudl
Hudl
16
Original post by 11234
I'll give you a hint, there are three situations we need to consider, when x<-5a/3 -5a/3<x<0 and x>0


Original post by 1 8 13 20 42
it is -x - a, yours expands to -x + a which is inconsistent with the equation you are given


I know the answer what I dont get is when we do modulus equations and we draw the graph and for example in this case the negative part of one graph the |x| - a graph crosses the postitive part of the other graph 3x + 5a

What I would normally do in this case is to put a negative in front of the equation underlining the negative part ie

-(x - a) = 3x + 5a
---> -x + a = 3x + 5a


The markscheme says its just -x - a = 3x + 5a etc I dont know why
Original post by Maham88
yeah i think they do c3 and c4 together


Ah okay, thanks for the link anyways :smile:
Original post by Frank Costello
Can someone explain what happens to the graph is transformed by the function f(|x|)


Reflect everything to the right of the y axis into the Y axis

So all the positive values for x. reflect them into the y axis. So everything on the right side of the line x=0 would be a reflection of the left side
can anyone help me on question 13 b) jan 2015 why does the cos(30t+16.7) have to equal to -1 when it is asking for the max value ?
https://drive.google.com/folderview?id=0B1ZiqBksUHNYak5FZDJHS1ZSTHM#list

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