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Edexcel A2 C3 Mathematics 12th June 2015

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Original post by anonwinner
Just woke up... Anyone else here?


yep
Original post by Hudl
Got a question from that june 13 paper, not gone to bed yet as trying to understand where I flawed. There are a few algebraic errors due to silly mistakes. Sill managed an A* but only got 58.

I'm confused as to why you found the maximum value for the denominator, if we want the minimum value for V shouldnt the value on the denominator be as small as possible so -25 in other words, that way you get 21/-25 which is smaller than 21/25?

for the velocity question part b q8 June 2013


EDIT


Also within the range we're given 0 < X < 150 we cant have cosX as 1


Velocity can never be negative and the RCos(x-a) graph is shifted to the right so you can get 1

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Is there any Jan 2015 c3 IAL paper?
Original post by Freddy-Francis
Is there any Jan 2015 c3 IAL paper?

yeah but it is a mix of c3 and c4
Original post by Maham88
yeah but it is a mix of c3 and c4


i was thinking why integration was there :s-smilie:
i try get my head around it but i still dont understand part b, how would you do it using part a can some give me a worked solution in detail please

Original post by studentwiz
i try get my head around it but i still dont understand part b, how would you do it using part a can some give me a worked solution in detail please



what paper is this ?
Original post by studentwiz
i try get my head around it but i still dont understand part b, how would you do it using part a can some give me a worked solution in detail please



b)

let a = (x+ pie/2)
b = (x+pie/6)

so.

2cos (A) = secB
2cosA = 1/cosB Multiply by cos B
2cosAcosB = 1
now u get the form as above.. so use that layout from part a.

At part A it says 2cosAcosB = cos(A+B) + cos(a-b)

sub in a and b
so cos(x+pie/2 + x + pie/6) + cos(x+pie/2 - (x + pie/6)) = 1
cos(2x + 2/3pie) + cos(1/3pie) = 1

so cos(2x +2/3pie) = 1/2
is that right?

x = pie/2, 5/6pie

and solve, i think :s-smilie:
(edited 8 years ago)
Original post by Maham88
what paper is this ?


solomon paper G
Original post by studentwiz
solomon paper G


Dude i solved it ^^ at least reply :biggrin:
Original post by Freddy-Francis
b)

let a = (x+ pie/2)
b = (x+pie/6)

so.

2cos (A) = secB
2cosA = 1/cosB Multiply by cos B
2cosAcosB = 1
now u get the form as above.. so use that layout from part a.

At part A it says 2cosAcosB = cos(A+B) + cos(a-b)

sub in a and b
so cos(x+pie/2 + x + pie/6) + cos(x+pie/2 - x + pie/6) = 1
cos(2x + 2/3pie) + cos(1/3pie) = 1

so cos(2x +2/3pie) = 1/2
is that right?

x = pie/2, 5/6pie

and solve, i think :s-smilie:


nice thank you! :smile:
Original post by Freddy-Francis
Dude i solved it ^^ at least reply :biggrin:


:biggrin:
Original post by studentwiz
nice thank you! :smile:


No Prob :tongue:
Getting close now, could someone just send a list of the all the formulas that we need to learn that aren't in the formula book please?
Original post by Maths,man
Getting close now, could someone just send a list of the all the formulas that we need to learn that aren't in the formula book please?


http://www.slideshare.net/anicholls1234/c3c4-formulae-everything-edexcel
Reply 2115
Avatar for Sants
Sants
Anyone ready for the exam!!!
what do you have to say for the sign change iteration proof question to get full marks
Original post by studentwiz
what do you have to say for the sign change iteration proof question to get full marks


since there is a change in sign there is a root between the intervals
Reply 2118
Avatar for Sants
Sants
Anyone realise that the qoutient rule is given in the formula booklet?
Original post by Sants
Anyone realise that the qoutient rule is given in the formula booklet?


But wastes time looking back :P

Do u really need to check :colondollar:

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