Can someone please explain how you do this Q?
SO2 + 2H2S 3S + 2H2O
(ii) 44.3 g of SO2 are mixed with 44.3 g of H2S.Calculate the maximum mass of sulfur that could be formed.Show your working.
Mark scheme:
1.BOTH moles SO2 = 44.3/64(.1) or 0.69AND moles H2S = 44.3/34(.1) or 1.3
2.SO2 in excess/ H2S is limiting (AW)
3.mass S formed (= 1.3 x 1.5 x 32.1) = 62.6 g[62.4 if 32 used as Ar](Allow any number between 62.4 and 63)
I dont understand what they did in step 3, or how they got step 2.