Edexcel A2 C4 Mathematics June 2015 - Official Thread

DI/DT=-16(0.5)^t(ln(0.5))
Sub in t=3
So it becomes -2ln0.5
Which is the same as ln(0.5^-2)
Which is equal to ln4


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oh....sorry thought the first bit was saying about using a substitute

sorry

DI/DT=-16(0.5)^t(ln(0.5))
Sub in t=3
So it becomes -2ln0.5
Which is the same as ln(0.5^-2)
Which is equal to ln4


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it's fine how would you integrate that?

thanks!

what do you mean? The question is just integrate sinx cos^3 x dx

I'm currently stuck on this question too!!
Can you please explain to me what you have done?

Have you done the R papers for June 2013 and June 2014? Or the C4 questions from the IAL C34 papers? They're written by the same team as write the ordinary ones.

First differentiate, differentiating a^x gives u a^xlna, then sub in t


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Whats the equation again?

First differentiate, differentiating a^x gives u a^xlna, then sub in t


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For real!

Slightly reassuring the the last paper I've just done before I do the real thing was the Jan 2014 paper, and managed to get 98UMS.. If only tomorrow goes that well.

OOOOOHHHHH!!!!!!!!!!!! is that c2 log laws at first?

When finding the shortest distance from the point to a line, how can you assume that a right angle is made between the point and the line?

How good are the gold papers in preparation for C4? I've done 2 today and plan to finish the other 2 by the end of today.... I've done all the papers from jan 2009 - june 14.... anyone got anymore suggestions to what other papers I should look at?
I probably have time for one more paper along with the 2 last gold papers that I'm planning to do.. wanna get a good sleep before tomorrow to reduce my chances of making stupid mistakes...

if $y(x) = a^x$, then $\log(y) = x\log(a)$; thus by implicit differentiation: $\dfrac{1}{y}\dfrac{dy}{dx} = \log(a) \implies \dfrac{dy}{dx} = y\log(a) \implies \boxed{\dfrac{dy}{dx} = a^x\log(a)}$

Use Chebysev's


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