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4756 OCR MEI FP2 22nd June 2015

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High grade boundaries.


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Original post by Dan205
Did you get -32 for the product of v?

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32 e^j(pi/2)


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Reply 102
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Dan205
8
Original post by Genty Boy


Uh oh... I got e^j(pi) :/

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Original post by Dan205
Uh oh... I got e^j(pi) :/

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For the first z value I got 2e^j(pi/10)...

Raise that to 5 I think is how you work it out...


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Reply 104
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Dan205
8
Original post by Genty Boy
For the first z value I got 2e^j(pi/10)...

Raise that to 5 I think is how you work it out...


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Nah that makes sense, I don't know what I did haha!

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Original post by Dan205
Nah that makes sense, I don't know what I did haha!

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I may be wrong.


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Original post by Dan205
Did you get -32 for the product of v?

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Fairly sure it was +32j
Original post by Genty Boy


It said simplified form so you had to leave it as just +32j
Overall, nice exam IMO
I think it'll be around 62 for an A
Original post by chizz1889
Fairly sure it was +32j


Yep, that's the same as 32e^pi/2 j
Reply 110
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_Caz_
10
Well that went surprisingly well. I didn't even expect to finish.

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Last integral was x/2 * ln ((1+x)/(1-x)) + 1/2 * ln(1-x^2) + c
Original post by sarcasmrules
Yep, that's the same as 32e^pi/2 j


Yeah but it said 'simplified form' which is 32j
Wow, that was such a nice exam, feeling pretty confident about that but probably will be around 66-68 for an A* :frown:

I got v^5 = 32j
Original post by chizz1889
Last integral was x/2 * ln ((1+x)/(1-x)) + 1/2 * ln(1-x^2) + c


I got that also.
M^4 = 43m^2 + 42m
For The PDP^-1 = M^4

The diagonal components of D were 1;0;2401
For the lambda3 the vector was (4,1,3)
Coordinates (a,b)?
Radius sqrt(a^2+b^2)?


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The eigenvalues were -1, 0, 7.

The eigenvector for 7 was (4,1,3) I think

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