CB=16sin(30)=8 BC=BD=8 So triangle CBD is isoceles with side lengths 12, 8 and 8 cm. Use pythagoras to find height: Root(8^2-6^2)=Root(38) Area = half base * height = (12/2)*root(38)=6 root 38
But from the pic you have submitted, it seems that ACD is 90 degrees, if it is the BCD is 30 and therefore since BC=BD the BC= 8 from Pythagoras theorm and sin30*8*12*0.5 = 24 so the area is 24 if the angle is as the pic which is 90
But from the pic you have submitted, it seems that ACD is 90 degrees, if it is the BCD is 30 and therefore since BC=BD the BC= 8 from Pythagoras theorm and sin30*8*12*0.5 = 24 so the area is 24 if the angle is as the pic which is 90
I did this really quickly, based on your diagram, check through to make sure the maths is ok
Your maths looks fine to me but I still don't what the answer is because everyone seems to be getting different ones. But thank you so much for your solution and I will post the answer on Wednesday so you can see if you were correct.