A level trigonometry
For part ii i know that the new range is 0 to 360 and have found one as as 27.4 but i dont know how to get the other answer?
Please help
Please help
Original post by uzer
but how do you do it without a graph because in the exam you dont have time to draw it
How did you do it in C2?
I don't have word on my laptop but I'm assuming another answer can be found using the trig graphs.
You don't have to go into amazing detail when drawing them, just a sketch will do. Aslong as you learn what they look like you should be fine (e.g. y=tanx repeats every 180 (or pi), y=sinx crosses through (0,0), (90, 1), (180, 0), (270, -1), (360, 0)).
You don't have to go into amazing detail when drawing them, just a sketch will do. Aslong as you learn what they look like you should be fine (e.g. y=tanx repeats every 180 (or pi), y=sinx crosses through (0,0), (90, 1), (180, 0), (270, -1), (360, 0)).
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